Answer:
The answer to your question is: c) $1354500
Step-by-step explanation:
Data:
Parcel1 = P1 = 1 mi2
Parcel2= P2= 5 acres
Price = $2100 / acre
Total price =
Need to convert 1 mi2 to acres
1 acre ------------------------ 0.001563 mi2
x ------------------------- 1 mi2
x = 639.8 acres
Now
1 acre ------------------------- $2100
639.8 acres ----------------- x
Parcel 1 cost = $1343580
1 acre ------------------------- $2100
5 acres --------------------- x
x = 10500
Total cost = cost P1 + cost P2
Total cost = $1343580 + $10500 = $ 1354080 The closest is letter c
Answer : The number is 4.
Step-by-step explanation:
<u>Given : </u>
six times a number, increased by 3 is is 27.
<u>To Find: </u>
The number.
<u>Solution : </u>
Let the number is x
six times a number is 6x
Increased by 3 = 6x+3
According to the given question :
<u>Solving the value x : </u>
6x+3 =27
6x = 27-3
6x = 24
x = 24/6
x = 4
Hence, the number is 4.
The initial value of the linear relationship is 5.
Solution:
- The y-intercept is the point where the line crosses at y-axis.
- The initial value of the linear function is the y-intercept.
On observing the graph, the line crosses y-axis at the point (0, 5).
So, y-intercept = 5
That is initial value = 5
Therefore the initial value of the linear relationship is 5.
She has $5.33 left
$9.00
-$3.67
————
$5.33
We start at 62 Fahrenheit. And every hour we drop two degrees. We want to know how long it took for the temperature to drop to 40 Fahrenheit.
If one hour passed, then the temperature dropped two degrees.
If two hours passed, then the temperature dropped 4 degrees.
See the pattern? We can define this as 2h. Where h represents time in hours.
We subtract 2h from 62.
We can write this as a function. F(h) = 62 - 2h.
Where F is the temperature in Fahrenheit. And h is the hour(s).
Now that we have the formula, let's plug in the value 40 Fahrenheit to see how long it took for the temperature to drop to 40 degrees.
40 = 62 - 2h
Subtract 62 from each side
-22 = -2h
Divide both sides by 2
h = 11
So, it took 11 hours for the temperature to drop to 40 Fahrenheit.
