Answer: dispersion forces, dipole-dipole and hydrogen bonds
Explanation:
Diagram A shows the Lewis structure (LS) of CH_2O. The formal charge on each atom is zero.
To get the formal charge (FC) on the atoms, cut each bond in half, as in <em>Diagram B</em>. Each atom gets the electrons on its side of the cut.
Formal charge = valence electrons in isolated atom - electrons on bonded atom
FC = VE - BE
<em>On O:
</em>
VE = 6
BE = 2 lone pairs 2 + 2 bonding electrons = 4 + 2 = 6
FC = 6 – 6 = 0.
<em>On H:
</em>
VE = 1
BE = 1 bonding electron
FC = 1 – 1 = 0
<em>On C:
</em>
VE = 4
BE = 1 in each single bond + 2 in the double bond = 2 + 2 = 4
FC = 4 - 4 = 0
The answer is group 1A.
In the ionic compound formula X₂SO₄, SO₄ has a -2 charge. Hence to balance this -2 charge of SO₄, X must have a +1 charge.
Group 1A elements form X⁺ type of ions because they are metals. So, they have the tendency to lose electrons.
Hence, X must belong to the 1A group.
Ionic Compounds-
- Ionic compounds are formed by the electrostatic attraction between the anions and the cations.
- Cations are positively charged ions that are formed due to the loss of electrons.
- And the anions are negatively charged ions that are formed due to the gain of electrons.
- Due to this, they have opposite charges and form bonds known as Ionic Bond.
To learn more about Ionic compounds, visit: brainly.com/question/9167977
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The engine ran for 10 second
Ok to answer this question we firsst need to fin the number of mol of Urea (CH4N2O). to do this we simply :
1 mol of urea =15/60.055 = 0.25mol
therefore 200g of water contain 0.25mol
the next step is to determine the malality of our solution in 200g of water, to do this we say:
200 g = 1Kg/1000g = 0.2kg
therefor 0.25mol/0.2Kg = 1.25mol/kg
and from the equation:
we know that i = 1
we are given Kf
b is the molality that we just calculated
therefore;
the solutions freezing point is -2.325°C