Set up a system of equations.
0.10d + 0.25q = 39.25
d + q = 250
Where 'd' represents the number of dimes, and 'q' represents the number of quarters.
d + q = 250
Subtract 'q' to both sides:
d = -q + 250
Plug in '-q + 250' for 'd' in the 1st equation:
0.10(-q + 250) + 0.25q = 39.25
Distribute 0.10:
-0.10q + 25 + 0.25q = 39.25
Combine like terms:
0.15q + 25 = 39.25
Subtract 25 to both sides:
0.15q = 14.25
Divide 0.15 to both sides:
q = 95
Now plug this into any of the two equations to find 'd':
d + q = 250
d + 95 = 250
Subtract 95 to both sides:
d = 155
So there are 95 quarters and 155 dimes.
A hockey puck is sliding on frictionless ice on an infinite hockey rink.
Its speed is 36 km/hour. How far does the puck slide in 10 seconds ?
(36 km/hr) x (1,000 m/km) x (1 hr/3600 sec) x (10sec) =
(36 x 1,000 x 10 / 3,600) meters = <em>100 meters</em>
What is the puck's speed in miles per hour ?
(36 km/hr) x (0.6214 mi/km) = <em>22.37 mi/hr</em>
Answer:
the answer is 6
Step-by-step explanation:
3×2-0×2=6
4(5x+1)(5x-1) = 0
1. Take out the GCF (in this case, 4)
4(25x^2-1) = 0
2. This can be further factored. Factor the values within the parenthesis
4(5x + 1)(5x -1) = 0