Answer: When using 645 L /s of O2 in a temperature and pressure of 195°C, 0.88 atm respectively, we will get 0.355Kg /s NO
Explanation:
- First we review the equation that represents the oxidation process of the NH3 to NO.
4NH3(g) + 5O2(g) ⟶4 NO(g) +6 H2O(l)
- Second we gather the information what we are going to use in our calculations.
O2 Volume Rate = 645 L /s
Pressure = 0.88 atm
Temperature = 195°C + 273 = 468K
NO molecular weight = 30.01 g/mol
- Third, in order to calculate the amount of NO moles produced by 645L/ s of O2, we must find out, how many moles (n) are 645L O2 by using the general gas equation PV =n RT
Let´s keep in mind that using this equation our constant R is 0.08205Lxatm/Kxmol
PV =n RT
n= PV / RT
n= [ 0.88atm x 645L/s] / [ (0.08205 Lxatm/Kxmol) x 468K]
n= 14.781 moles /s of O2
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Fourth, now by knowing the amount of moles of O2, we can use the equation to calculate how many moles of NO will be produced and then with the molecular weight, we will finally know the total mass per second .
14.781 moles /s of O2 x 4moles NO / 5 moles O2 x 30.01g NO / 1 mol NO x 1Kg NO /1000g NO = 0.355Kg /s NO
Answer:
Li⁺, Na⁺ (group 1); N⁻³ (group 15)
Explanation:
Li and Na belong to group 1 of the periodic table so they coincide in the valence electrons which, being group 1, is a single electron.
They are very willing to lose it because they have little electronic affinity. In addition, both elements enter the alkali metal group (all of group 1)
They are cations, as they make ionic bonds.
N is an element from group 15. It is a nonmetal and has 5 electrons in its last layer as all the elements that make up its group, P, As, Sb so it would subtract 3 more electrons to have its last complete level and thus reach noble gas configuration.
Nitrogen can make covalent bonds, for example with O, where they form anions because it can gain electrons.
<span>the surfactant molecule has 2 ends
a hydrophilic (water attracting)
lipophilic(oil attracting)
they create a push and pull process that causes the dirt to e balled up and rinsed away.</span>