05.06)Which of the following best describes interval C on the graph shown?

Mathematics

2 answers:

Korolek [52]2 years ago

8 0

Linear decreasing

I haven't learned this is class yet, but I had a bf that taught me this

Otrada [13]2 years ago

8 0

<h2>Answer:</h2>

The term that best describes the interval C on the graph is:

Linear decreasing.

<h2>Step-by-step explanation:</h2>

Clearly from the graph we could observe that the graph of the function is linear in the interval C as the graph is a straight line. Also as the slope of line is negative( since with the increasing x the value of the function decreases)

Hence, the function is decreasing in the interval C.

Hence, the term that describes the function in interval C is:

Linear decreasing.

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One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
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the center is (h,k) and the radius is r

and the distance formula is
distance between $(x_1,y_1)$ and $(x_2,y_2)$ is
$D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle

so
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$(x-(-2))^2+(y-3)^2=(\sqrt{18})^2$
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the radius is $3\sqrt{2}$
center is (-2,3)

find distance between (8,4) and (-2,3)

$D=\sqrt{(8-(-2))^2+(4-3)^2}$
$D=\sqrt{(8+2)^2+(1)^2}$
$D=\sqrt{10^2+1}$
$D=\sqrt{100+1}$
$D=\sqrt{101}$

$r=3\sqrt{2}$ ≈4.2
$D=\sqrt{101}$ ≈10.04

do r<D

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