x-coordinates for the maximum points in any function f(x) by f'(x) =0 would be x = π/2 and x= 3π/2.
<h3>How to obtain the maximum value of a function?</h3>
To find the maximum of a continuous and twice differentiable function f(x), we can firstly differentiate it with respect to x and equating it to 0 will give us critical points.
we want to find x-coordinates for the maximum points in any function f(x) by f'(x) =0
Given f(x)= 4cos(2x -π)
In general
from x = 0 to x = 2π :
when k =0 then x = π/2
when k =1 then x= π
when k =2 then x= 3π/2
when k =3 then x=2π
Thus, X-coordinates of maximum points are x = π/2 and x= 3π/2
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100 inches Over 1 minute times 1 foot over 12 inches
Answer:
$4.50 each
Step-by-step explanation:
sorry if I'm wrong
(5/6) for one costume. Make 9.
(5/6)*9/1 = 45/6
Answer:
0.00003 seconds (30 millionths of a second!)
Step-by-step explanation:
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