Where's your number line?
Answer:
BC=3
Step-by-step explanation:
<em>We </em><em>can </em><em>solve </em><em>this </em><em>by </em><em>eliminating</em><em> </em><em>given </em><em>detail </em><em>of </em><em>A.</em>
AC=13 , AB=10
<u>To </u><u>find </u><u>BC,</u><u> </u><u>We </u><u>minus </u><u>A</u><u>C</u><u> </u><u>With </u><u>AB</u>
BC= AC-AB
<u>BC=3</u>
3 Is the final answer
I hope this helps, dont hesitate to ask for any question.
Mark me as brainliest is appreciated.Tq!!
Answer:
C. 1/(x^2 +1) > 0
Step-by-step explanation:
The cube of a negative number is negative, eliminating choices B and D for certain negative values of x.
1/x^2 is undefined for x=0, so cannot be compared to zero.
The value 1/(x^2+1) is positive everywhere, so that is the expression you're looking for.
1/(x^2 +1) > 0
Answer:
x is at least -2
Step-by-step explanation: