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2 years ago

How does acceleration affect speed and velocity

1 answer:

5 0

Acceleration is a vector quantity that is defined as the rate at which an object changes its velocity. An object is accelerating if it is changing its velocity.

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A disk ring of inner radius a and outer radius b lying on the y − z plane has a uniform surface electric charge density +σ(>

solmaris [256]

Answer:

a) V = k 2π σ (√(b² + x²) - √ (a² + x²)) ,

b) E = - k 2π σ x (1 /√(b² + x²) - 1 /√(a² + x²))

Explanation:

a) The expression for the electric potential is

V = k ∫ dq / r

For this case, consider the disk formed by a series of concentric rings of radius r and width dr, the distance of each ring to point P

R = √(x² + r²)

The charge on a ring is

σ = dq / dA

The area of a ring is

A = π r

dA = 2π r dr

So the charge is

dq = σ 2π r dr

We substitute

V = k σ 2pi ∫ r dr / √(r² + x²)

We integrate

V = k 2π σ √(r² + x²)

We evaluate from the lower limit r = a to the upper limit r = b

V = k 2π σ (√(b² + x²) - √ (a² + x²))

b) the electric field and the potential are related

E = - dV / dx

E = - k 2π σ (1/2 2x /√(b² + x²) - ½ 2x /√(a² + x²))

E = - k 2π σ x (1 /√(b² + x²) - 1 /√(a² + x²))

7 0

2 years ago

The opening to the windpipe is called the _____.

Nina [5.8K]

Glottis is the organ that is considered to be the opening to the windpipe. It consists of vocal chords wherein voice modulation usually takes place. The production of the sounds of the organ can be mainly attributed to the "buzzing" vibration inside the vocal chords wherein they vibrate.

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2 years ago

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What is the hidden gene called

vagabundo [1.1K]

The hidden gene is called recessive

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2 years ago

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Two go-carts, A and B, race each other around a 1.0 track. Go-cart A travels at a constant speed of 20.0 /. Go-cart B accelerate

maria [59]

Complete Question

Q. Two go-carts, A and B, race each other around a 1.0km track. Go-cart A travels at a constant speed of 20m/s. Go-cart B accelerates uniformly from rest at a rate of 0.333m/s^2. Which go-cart wins the race and by how much time?

Answer:

Go-cart A is faster

Explanation:

From the question we are told that

The length of the track is $l = 1.0 \ km = 1000 \ m$

The speed of A is $v__{A}} = 20 \ m/s$

The uniform acceleration of B is $a__{B}} = 0.333 \ m/s^2$

Generally the time taken by go-cart A is mathematically represented as

$t__{A}} = \frac{l}{v__{A}}}$

=> $t__{A}} = \frac{1000}{20}$

=> $t__{A}} = 50 \ s$

Generally from kinematic equation we can evaluate the time taken by go-cart B as

$l = ut__{B}} + \frac{1}{2} a__{B}} * t__{B}}^2$

given that go-cart B starts from rest u = 0 m/s

$1000 = 0 *t__{B}} + \frac{1}{2} * 0.333 * t__{B}}^2$

=> $1000 = 0 *t__{B}} + \frac{1}{2} 0.333 * t__{B}}^2$

=> $t__{B}} = 77.5 \ seconds$

Comparing $t__{A}} \ and \ t__{B}}$ we see that $t__{A}}$ is smaller so go-cart A is faster

3 0

2 years ago

observe the figure given carefully volume of water in each vessel is shown arrange them in order of decreasing pressure at the b

mihalych1998 [28]

Answer:

See the explanation below

Explanation:

The pressure is defined as the product of the density of the liquid by the gravitational acceleration by the height, and can be easily calculated by means of the following equation.

$P=Ro*g*h$

where:

Ro = density of the fluid [kg/m³]

g = gravity acceleration = 9.81 [m/s²]

h = elevation [m]

In this way we can understand that the greater pressure is achieved by means of the height of the liquid, that is, as long as the fluid has more height, greater pressure will be achieved at the bottom.

Therefore in order of decreasing will be

The largest pressure with the largest height of the liquid, container B. The next is obtained with container D, the next with container A and the lowest pressure with container C.

The pressure decreases as we go from the container B - D - A - C

5 0

2 years ago