A)
Vf² = vi² + 2ad Subtract 2ad from both sides
Vf² - 2ad = vi² Find the square roots of both sides
√(Vf² - 2ad) = √(vi²) Cancel out the squares with the square roots
Vf - √(2ad) = vi Switch the sides to make it easier to read
vi = Vf - √(2ad)
B) Vf² = vi² + 2ad Subtract vi² from both sides
Vf² - vi² = 2ad Divide both sides by 2a
(Vf² - vi²) / 2a = d Switch the sdies to make it easier to read
d = (Vf² - vi²) / 2a
Answer:
a=0
Step-by-step explanation:
im prbly wrong pls tell me if im wrong
12x-3y12x-3y (x=-14x=-14 or x=1) and( y=3)
12(1)-3(3)12(1)-3(3)
12-9*12-9
12-108-9
96-9
87
We look for the minimum of each function.
For f (x) = 3x2 + 12x + 16:
We derive the function:
f '(x) = 6x + 12
We match zero:
6x + 12 = 0
We clear the value of x:
x = -12/6
x = -2
We substitute the value of x in the equation:
f (-2) = 3 * (- 2) ^ 2 + 12 * (- 2) + 16
f (-2) = 4
For g (x) = 2sin(x-pi):
From the graph we observe that the minimum value of the function is:
y = -2
Answer:
A function that has the smallest minimum y-value is:
y = -2