Answer:
Height of tree is <em>15 m.</em>
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Step-by-step explanation:
Given that student is 20 m away from the foot of tree.
and table is 1.5 m above the ground.
The angle of elevation is: 34°28'
Please refer to the attached image. The given situation can be mapped to a right angled triangle as shown in the image.
AB = CP = 20 m
CA = PB = 1.5 m
= 34°28' = 34.46°
To find TB = ?
we can use trigonometric function tangent to find TP in right angled
Now, adding PB to TP will give us the height of tree, TB
Now, height of tree TB = TP + PB
TB = 13.72 + 1.5 = 15.22 <em>15 m</em>
Its Letter B -0.5
negative because its slope is negative (from left to right it's going downward)
so there are 2 negavite numbers in the choices, -0.5 and -0.95.
The nearer the value to 1 the less scatter it is. The farther the value to 1 (means nearer to 0) the more scatter it is. Because the plot in the picture is mostly scattered the value should be nearer to 0. It is negative 0.5.
I believe it is 83 because a straight line is 180 degrees