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2 years ago

What is the correct description of the components of an ATP molecule?

1 answer:

4 0

It's adenosine triphosphate !

it has Penrose sugar and phosphate as backbone !
and nitrogenous base ... adenine.... in the middle !

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Which term describes the molecule shown below?

Aleks04 [339]

Answer:

Saturated alkyne

Explanation:

6 0

2 years ago

Please and thank you!

Valentin [98]

Answer:

7.5 moles of O₂.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2KClO₃ —> 2KCl + 3O₂

From the balanced equation above,

2 moles of KClO₃ decomposed to produce 3 moles of O₂.

Finally, we shall determine the number of mole of O₂ produced by the decomposition of 5 moles of KClO₃. This can be obtained as follow:

From the balanced equation above,

2 moles of KClO₃ decomposed to produce 3 moles of O₂.

Therefore, 5 moles of KClO₃ will decompose to produce = (5 × 3)/ 2 = 7.5 moles of O₂.

Thus, 7.5 moles of O₂ were obtained from the reaction.

3 0

2 years ago

I need to know how to do this problem

ser-zykov [4K]

Neeeeeeeeeeeeee neeeee

4 0

2 years ago

What element is being reduced in the redox reaction? H2O2+ ClO2- > ClO- + O2

slava [35]

Answer:

Explanation:

Because the oxidation state reduces from+3 in ClO2- to +1 in ClO- and oxygen is being lost

6 0

2 years ago

The system described by the reaction CO(g)+Cl2(g)⇌COCl2(g) is at equilibrium at a given temperature when PCO= 0.26 atm , PCl2= 0

givi [52]

<u>Answer:</u> The new pressure of CO is 0.09 atm

<u>Explanation:</u>

For the given chemical reaction:

$CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)$

The expression of $K_p$ for above equation follows:

$K_p=\frac{p_{COCl_2}}{p_{CO}\times p_{Cl_2}}$ .......(1)

We are given:

$p_{COCl_2}=0.66atm\\p_{CO}=0.26atm\\p_{Cl_2}=0.15atm$

Putting values in above equation, we get:

$K_p=\frac{0.66}{0.15\times 0.26}\\\\K_p=16.92$

Addition pressure of chlorine added = 0.39 atm

Now, the equilibrium is re-established:

$CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)$

Initial: 0.26 0.15 0.66

At eqllm: 0.26-x 0.54 0.66+x

Putting values in expression 1, we get:

$16.92=\frac{(0.66+x)}{(0.26-x)\times 0.54}\\\\x=0.17$

So, new pressure of CO = 0.26 - x = (0.26 - 0.17) = 0.09 atm

Hence, the new pressure of CO is 0.09 atm

4 0

2 years ago