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2 years ago

How can I determine the question I circled? I’m stuck, please help (look at photo)

Mathematics

1 answer:

Semenov [28]2 years ago

7 0

i dont really know but im guessing use ratios. like 4:total volunteers

or something like that

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how many solutions does this equation have 15x-5 3=5x+4 a no solutions b. exactly one solution c. exactly two solution d. infini

velikii [3]

Answer:

one solution! & that would be be 57/10. hopefully that's correct.

Step-by-step explanation:

7 0

2 years ago

Ratio of cupcakes to muffins at a bakery is 6:5 the total is 99. how many cupcakes

sleet_krkn [62]

6+5 = 11

99/11 = 9

9x6 = 54

so 54 cupcakes

Hope this helps, and May the Force Be With You!

-Jabba

8 0

2 years ago

Given rectangles LMNO and PQRS, which statement explains a way to determine if the two figures are similar?

allochka39001 [22]

Answer:

Step-by-step explanation:

<u>Definition:</u> Two rectangles are similar when they have corresponding sides proportional are proportional by dilation.

For example, rectangles with sides 3 cm, 4cm and 6 cm, 8 cm are similar, but rectangles with sides 3 cm, 4 cm and 6 cm, 10 cm are nor similar.

Since all angles in rectangle are always right angles, then options A and C are false (in terms of your question).

Option D is false too, because translation doesn't change the length, and in this case two rectangles are congruent.

Option B is true according to definition.

3 0

2 years ago

Read 2 more answers

HELP ASAP PLSSSSSSS

scoundrel [369]

Answer:

x=3

Step-by-step explanation:

8*3 = 24

4*3=12

24-12=12

5 0

7 months ago

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A right cylinder has a radius of r inches and height of 2r inches.

lys-0071 [83]

Answer:

Part a) The lateral area is $4r^{2} \pi \ in^{2}$

Part b) The area of the two bases together is $2r^{2} \pi\ in^{2}$

Part c) The surface area is $6r^{2} \pi\ in^{2}$

Step-by-step explanation:

we know that

The surface area of a right cylinder is equal to

$SA=LA+2B$

where

LA is the lateral area

B is the area of the base of cylinder

we have

$r=r\ in$

$h=2r\ in$

Part a) Find the lateral area

The lateral area is equal to

$LA=2\pi rh$

substitute the values

$LA=2\pi r(2r)$

$LA=4r^{2} \pi\ in^{2}$

Part b) Find the area of the two bases together

The area of the base B is equal to

$B=r^{2} \pi\ in^{2}$

the area of the two bases together is

$2B=2r^{2} \pi\ in^{2}$

Part c) Find the surface area of the cylinder

$SA=LA+2B$

we have

$LA=4r^{2} \pi\ in^{2}$

$2B=2r^{2} \pi\ in^{2}$

substitute

$SA=4r^{2} \pi+2r^{2} \pi=6r^{2} \pi\ in^{2}$

4 0

2 years ago

Read 2 more answers