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2 years ago

Problems due Monday.

Mathematics

2 answers:

Ilya [14]2 years ago

8 0

11) x = 6
12) x = 7/4

Leya [2.2K]2 years ago

5 0

11. 2+6x+4=3x+12Step 1: Simplify both sides of the equation.2+6x+4=3x+12(6x)+(2+4)=3x+12(Combine Like Terms)6x+6=3x+126x+6=3x+12Step 2: Subtract 3x from both sides.6x+6−3x=3x+12−3x3x+6=12Step 3: Subtract 6 from both sides.3x+6−6=12−63x=6Step 4: Divide both sides by 3.3x3=63x=2Answer:x=212.−5+8x+2=4x+4Step 1: Simplify both sides of the equation.−5+8x+2=4x+4(8x)+(−5+2)=4x+4(Combine Like Terms)8x+−3=4x+48x−3=4x+4Step 2: Subtract 4x from both sides.8x−3−4x=4x+4−4x4x−3=4Step 3: Add 3 to both sides.4x−3+3=4+34x=7Step 4: Divide both sides by 4.4x4=7/4x=7/4Answer:x=7/4

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2 years ago

Read 2 more answers

1.13 Thank you! (Sorry it’s so blurry)

VikaD [51]

$\sqrt[8]{48^4}$ can be rewritten as $48^4$ to the $\frac{1}{8}$ power:

$(48^4)^ \frac{1}{8}$

Now, applying exponent rules (multiply exponent inside parentheses by the one outside parentheses), we get:

$(48^ \frac{1}{2})$

This is equivalent to $\sqrt{48}$ , so now, we just simplify:

$\sqrt{48}= \sqrt{16*3}= \sqrt{16}* \sqrt{3}=4 \sqrt{3}$

So:

$\sqrt[8]{48^4} =4 \sqrt{3}$

4 0

3 years ago