They are both right triangles so we can use the Pythagorean
theorem to solve.
6. B = sqrt(15^2-9^2)
B = 12 mm
7. B = sqrt(26^2-10^2)
B = 24 Cm
Now, multiply both sides by 6 and you get.....
df+10=6g
now, subtract 10 on both sides and you get.....
df=6g-10
now divide both sides by d to get f by itself and you get........
Set x as adult tickets.
Set y as children's tickets.
x + y = 15
30x + 20y = 270
Solve for x in the first equation.
x + y = 15
x = 15 - y
Plug this into the second equation.
30x + 20y = 270
30(15 - y) + 20y = 270
450 - 30y + 20y = 270
450 - 10y = 270
-10y = -180
y = 18
If there is 18 childrens tickets, there should be -3 adult tickets.
This is impossible, and this impossible answer occured because the question is written wrong.
There are a total of 15 tickets
The smallest costing ticket is the childrens ticket, which costs 20$.
If he only bought children tickets, this would be 20x15 which is 300$.
300$ is over 270$, which makes the question impossible.
Answer:
What did you do? What is this mess but thanks for the points
Step-by-step explanation:
