Answer:
First, for end behavior, the highest power of x is x^3 and it is positive. So towards infinity, the graph will be positive, and towards negative infinity the graph will be negative (because this is a cubic graph)
To find the zeros, you set the equation equal to 0 and solve for x
x^3+2x^2-8x=0
x(x^2+2x-8)=0
x(x+4)(x-2)=0
x=0 x=-4 x=2
So the zeros are at 0, -4, and 2. Therefore, you can plot the points (0,0), (-4,0) and (2,0)
And we can plug values into the original that are between each of the zeros to see which intervals are positive or negative.
Plugging in a -5 gets us -35
-1 gets us 9
1 gets us -5
3 gets us 21
So now you know end behavior, zeroes, and signs of intervals
Hope this helps
You would multiply the area by the height
Hope this helps
The answer is 2160
Answer:
D.) because it cannot be expressed as a ratio of integers
Step-by-step explanation:
The root of any integer that is not a perfect square is irrational. 5 is not a perfect square, so is irrational—it cannot be expressed as the ratio of integers.
__
<em>Proof</em>
Suppose √5 = p/q, where p and q are mutually prime. Then p² = 5q².
If p is even, then q² must be even. We know that √2 is irrational, so the only way for q² to be even is for q to be even—contradicting our requirement on p and q.
If p is odd, then both p² and q² will be odd. We can say p = 2n+1, and q = 2m+1, so we have ...
p² = 5q²
(2n+1)² = 5(2m+1)²
4n² +4n +1 = 20m² +20m +5
4n² +4n = 4(4m² +4m +1)
n(n+1) = (2m+1)²
The expression on the left will be even for any integer n; the expression on the right will be odd for any integer m. This equation cannot be satisfied for any integers m and n, so contradicting our assumption √5 = p/q.
We have shown using "proof by contradiction" that √5 cannot be the ratio of integers.
Answer:
y = 1/2x - 2
Step-by-step explanation:
Slope: 1/2
Point: (0, -2)
y-intercept: -2 - (1/2)(0) = -2
Answer:
60000
Step-by-step explanation:
56763 so you're going to take that number and you're going to run it to the nearest thousands by doing that you're going to take the six and six is either closest to zero or 10 and it is closer to 10 which would be your answer so you're going to add these zero replacing the six seven six and three in the equation and making me five of six by adding the one from the number 10 if you have any other questions text me if that doesn't make sense