Can you help me solve this

A boat is heading towards a lighthouse, where Luis is watching from a vertical distance of 107 feet above the water. Luis measur

Crazy boy [7]

Using the slope concept, it is found that the distance from point A to point B is of 465 feet.

<h3>What is a slope?</h3>

The slope is given by the vertical change divided by the horizontal change, and it's also the tangent of the angle of depression.

To find the horizontal position at point A, we have that:

tan(10º) = 107/dA

dA = 107/tan(10º)

dA = 607.

For the horizontal position at point B, we have that:

tan(37º) = 107/dB

dB = 107/tan(37º)

dB = 142.

Hence the distance is given by:

D = dA - dB = 607 - 142 = 465.

More can be learned about the slope concept at brainly.com/question/18090623

#SPJ1

6 0

1 year ago

Help if you’re good at math I’ll give brainliest

boyakko [2]

Answer:

(4,2)

Step-by-step explanation:

Just by looking at the graph, you can see that they intersect at (4,2). But just to check:

x - 2 = -0.5x + 4

1.5x = 6

x = 4

y = 4 - 2 = 2

(4,2)

6 0

2 years ago

Read 2 more answers

For the following rectangular prism, find the length of the diagonal connecting A to B. Round to the nearest tenth.

meriva

Answer:

I think it is 192

Step-by-step explanation:

Volume of cube: 5 x 4 x 8 = 160

Area of diagonal: 160/2 = 80

Length of diagonal: 80 / 0.5 x 3 = 480

AB = 480 / 5 x 2 = 192

8 0

1 year ago

Find the directional derivative of the function at the given point in the direction of the vector v. h(r, s, t) = ln(3r + 6s + 9

vodka [1.7K]

Answer:

$D_\overrightarrow{\rm v}$ $h(r,s,t)=(\frac{2}{7}\overrightarrow{\rm i})*(\frac{1}{r+2s+3t})+(\frac{6}{7}\overrightarrow{\rm j})*(\frac{2}{r+2s+3t})+(\frac{3}{7}\overrightarrow{\rm k})*(\frac{3}{r+2s+3t})$

Step-by-step explanation:

First, let’s check to see if the direction vector is a unit vector:

$||v||=\sqrt{(14)^{2} +(42)^{2} +(21)^{2} } =\sqrt{2401} =49$

It’s not a unit vector. therefore let's divide the vector by its magnitude in order to convert it into a unit vector:

$\overrightarrow{\rm v}=(\frac{14}{49}\overrightarrow{\rm i})+(\frac{42}{49}\overrightarrow{\rm j})+(\frac{21}{49}\overrightarrow{\rm k})= (\frac{2}{7}\overrightarrow{\rm i})+(\frac{6}{7}\overrightarrow{\rm j})+(\frac{3}{7}\overrightarrow{\rm k})$

Now, the directional derivative is given by:

$D_\overrightarrow{\rm v}$ $h(r,s,t)=\frac{\partial h(r,s,t)}{\partial r}\overrightarrow{\rm i} + \frac{\partial h(r,s,t)}{\partial s}\overrightarrow{\rm j} + \frac{\partial h(r,s,t)}{\partial t}\overrightarrow{\rm k}$

So let's calculate the partial derivates:

$\frac{\partial }{\partial r} ln(3r+6s+9t)=\frac{3}{3r+6s+9t}=\frac{1}{r+2s+3t}$

$\frac{\partial }{\partial s} ln(3r+6s+9t)=\frac{6}{3r+6s+9t}=\frac{2}{r+2s+3t}$

$\frac{\partial }{\partial t} ln(3r+6s+9t)=\frac{9}{3r+6s+9t}=\frac{3}{r+2s+3t}$

Therefore:

$D_\overrightarrow{\rm v}$ $h(r,s,t)=(\frac{2}{7}\overrightarrow{\rm i})*(\frac{1}{r+2s+3t})+(\frac{6}{7}\overrightarrow{\rm j})*(\frac{2}{r+2s+3t})+(\frac{3}{7}\overrightarrow{\rm k})*(\frac{3}{r+2s+3t})$

3 0

2 years ago

Write this as a faction in lowest term<br> 40 minutes to 30 minutes is?

horsena [70]

10/20 is the lowest fraction term

4 0

2 years ago