All categories

2 years ago

Please help 10x+8 =12x-18

Mathematics

2 answers:

Zigmanuir [339]2 years ago

6 0

Answer: 13

Step-by-step explanation:

10x+8=12x−18

Step 1: Subtract 12x from both sides.

10x+8−12x=12x−18−12x

−2x+8=−18

Step 2: Subtract 8 from both sides.

−2x+8−8=−18−8

−2x=−26

Step 3: Divide both sides by -2.

−2x - 2

−26-2

So , x=13

Hoped I helped -

Sleepy~

Nady [450]2 years ago

3 0

Answer: $x$ = 13

1. 10 $x$ + 8 − 12 $x$ = 12 $x$ − 18 − 12 $x$

−2 $x$ + 8 = −18

2. −2 $x$ + 8 − 8 = −18 − 8

−2 $x$ = −26

3. Split both sides by 2.

x = 13

You might be interested in

Determine formula of the nth term 2, 6, 12 20 30,42

nalin [4]

Check the forward differences of the sequence.

If $\{a_n\} = \{2,6,12,20,30,42,\ldots\}$ , then let $\{b_n\}$ be the sequence of first-order differences of $\{a_n\}$ . That is, for n ≥ 1,

$b_n = a_{n+1} - a_n$

so that $\{b_n\} = \{4, 6, 8, 10, 12, \ldots\}$ .

Let $\{c_n\}$ be the sequence of differences of $\{b_n\}$ ,

$c_n = b_{n+1} - b_n$

and we see that this is a constant sequence, $\{c_n\} = \{2, 2, 2, 2, \ldots\}$ . In other words, $\{b_n\}$ is an arithmetic sequence with common difference between terms of 2. That is,

$2 = b_{n+1} - b_n \implies b_{n+1} = b_n + 2$

and we can solve for $b_n$ in terms of $b_1=4$ :

$b_{n+1} = b_n + 2$

$b_{n+1} = (b_{n-1}+2) + 2 = b_{n-1} + 2\times2$

$b_{n+1} = (b_{n-2}+2) + 2\times2 = b_{n-2} + 3\times2$

and so on down to

$b_{n+1} = b_1 + 2n \implies b_{n+1} = 2n + 4 \implies b_n = 2(n-1)+4 = 2(n + 1)$

We solve for $a_n$ in the same way.

$2(n+1) = a_{n+1} - a_n \implies a_{n+1} = a_n + 2(n + 1)$

Then

$a_{n+1} = (a_{n-1} + 2n) + 2(n+1) \\ ~~~~~~~= a_{n-1} + 2 ((n+1) + n)$

$a_{n+1} = (a_{n-2} + 2(n-1)) + 2((n+1)+n) \\ ~~~~~~~ = a_{n-2} + 2 ((n+1) + n + (n-1))$

$a_{n+1} = (a_{n-3} + 2(n-2)) + 2((n+1)+n+(n-1)) \\ ~~~~~~~= a_{n-3} + 2 ((n+1) + n + (n-1) + (n-2))$

and so on down to

$a_{n+1} = a_1 + 2 \displaystyle \sum_{k=2}^{n+1} k = 2 + 2 \times \frac{n(n+3)}2$

$\implies a_{n+1} = n^2 + 3n + 2 \implies \boxed{a_n = n^2 + n}$

6 0

1 year ago

Please look at screen shot

Mnenie [13.5K]

Answer:

Quick Clean..........

3 0

1 year ago

In a photograph, a house is 4 inches wide and 6 inches tall. The photograph is enlarged while keeping proportional dimensions, a

AlekseyPX

Since you keep proportional dimensions, the proportion between the old and new dimensions must be the same. So, if we call the new height $h$ , the preservation of the width/height ratio is written as