Answer:
predators consuming prey transfers the energy that the prey original received from plants which get their energy from the sun
Crop rotation methods in the use of legumes.
Answer:
The correct answer is Each nucleotide is connected to three nitrogenous bases.
- Deoxyribonucleic acid (DNA) is a genetic material composed of nucleotides.
- Each nucleotide is made up of three elements: a phosphate group, a sugar group (deoxy ribose), and a nitrogenous base.
- There are four types of nitrogenous bases found in the DNA : adenine (A), guanine (G), thymine (T), and cytosine (C).
- Phosphate binds to a sugar group with the help of ester bond and sugar binds to a nitrogenous base with the help of glycosidic bond.
- Nucleotides bind with each other with the help of phospodiester bond to form the polynucleotide chain.
- The two nucleotide chains are held together with the help of hydrogen bonding between nitrogenous bases of two strands. They form the double helical structure of the DNA.
- The two strands lei in anti-parallel orientation.
- It is also important to note that adenine always binds with thymine with the help of two hydrogen bonds and guanine always binds with cytosine with the help of three hydrogen bonds.
A process in which molecules move across a semipermeable membrane until the number of molecules of water is nearly equal on both sides..
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<em><u>Tq</u></em></h2>
1) Data:
dominant allele- A
recessive allele- a
Heterozygotic: Aa (only carries the allele)
Homozygotic recessive: aa (expresses the disease)
Homozygotic dominant: AA (doesn't carry or expresses the disease)
2)The first cross between Jim and his first wife originated a offspring with
<span>cystic fibrosis</span>. That offspring has the genotype aa and for that to happen both parents need to be a least carriers or express the disease. The exercise rules out the second case, which makes Jim a carrier.
3)Now between Jim and Martha:
From the previous step, we already found that jim is a carrier and the exercise also tells us that Martha is one too. So, their genotype is: Aa.
The cross: Aa x Aa
The probability:
1/4 aa = 25%
2/4 =Aa
1/4 - AA
the probability of having a <span>baby with cystic fibrosis is 25%</span>