Solve for V2 when P1 = 1.0 atm V1 = 22.4 L and P2 = 4.0 atm This is a Boyle’s law gas problem

Please help This is for my chemistry class and I need to get it done but I’m lost and need answers

Vanyuwa [196]

Answer:

chlorine is a non metal.

sodium is a alkali metal.

helium is a noble gas.

nickel is a transition metal

5 0

1 year ago

Calculate the mass defect for the formation of phosphorus-31. The mass of a phosphorus-31 nucleus is 30.973765 amu. The masses o

Nata [24]

Answer: The mass defect for the formation of phosphorus-31 is 0.27399

Explanation:

Mass defect is defined as the difference in the mass of an isotope and its mass number.

The equation used to calculate mass defect follows:

$\Delta m=[(n_p\times m_p)+(n_n\times m_n)]-M$

where,

$n_p$ = number of protons

$m_p$ = mass of one proton

$n_n$ = number of neutrons

$m_n$ = mass of one neutron

M = mass number of element

We are given:

An isotope of phosphorus which is $_{15}^{31}\textrm{P}$

Number of protons = atomic number = 15

Number of neutrons = Mass number - atomic number = 31 - 15 = 16

Mass of proton = 1.00728 amu

Mass of neutron = 1.00866 amu

Mass number of phosphorus = 30.973765 amu

Putting values in above equation, we get:

$\Delta m=[(15\times 1.00728)+(16\times 1.00866)]-30.973765\\\\\Delta m=0.27399$

Hence, the mass defect for the formation of phosphorus-31 is 0.27399

8 0

2 years ago

What type of charge does each part of an atom have (positive, negative, no charge)

Masteriza [31]

Answer:
P-positive
N-negative
E-no charge

6 0

2 years ago

Read 2 more answers

Which of the four cars had the least net force applied to it when it was launched down the ramp

castortr0y [4]

The least net force applied : Car 3(12 N)

<h3>Further explanation </h3>

Newton's 2nd law explains that the acceleration produced by the resultant force on an object is proportional and in line with the resultant force and inversely proportional to the mass of the object

∑F = m. a

Car 1 ⇒m=0.5 kg, a=36 m/s²

$\tt \sum F=0.5\times 36=18~N$

Car 2⇒m=0.8 kg, a=50 m/s²

$\tt \sum F=0.8\times 50=40~N$

Car 3⇒m=0.6, a=20 m/s²

$\tt \sum F=0.6\times 20=12~N$

Car 4⇒m=1, a=19~m/s²

$\tt \sum=1\times 19=19~N$

5 0

2 years ago

Answer the following questions based on the reaction below: NaOH(aq) + KHP(s) --> NaKP(aq)+H2O(I)

Natali [406]

Answer:

a) 1.44g

b) 77.3%

Explanation:

1. Chemical balanced equation (given)

$NaOH(aq)+ KHP(s)\rightarrow NaKP(aq)+H_2O(l)$

2. Mole ratio

$1molNaOH(aq):1molKHP(s)$

This is, 1 mol of NaOH will reacts with 1 mol of KHP.

3. Find the number of moles in 72.14 mL of the base

$Molarity=\text{number of moles of solute}/\text{volume of solution in liters}$

$\text{Volume of solution}=72.14mL=0.07214liters$

$\text{Number of moles of NaOH}=0.0978M\times 0.07214liter=0.007055mol$

4. Find the number of grams of KHP that reacted

The number of moles of KHP that reacted is equal to the number of moles of NaOH, 0.007055 mol

Convert moles to grams:

mass = number moles × molar mass = 0.007055mol × 204.23g/mol

mass = 1.4408 g.

You have to round to 3 significant figures: 1.44 g (because the molarity is given with 3 significant figures).

5. Find the percentage of KHP in the sample

The percentage is how much of the substance is in 100 parts of the sample.

The formula is:

% = (mass of substance / mass of sample) × 100

% = (1.4408g/ 1.864g) × 100 = 77.3%

7 0

2 years ago