Answer: N = 2.78 × 10^23 atoms
There are N = 2.78 × 10^23 atoms in 70g of Au2cl6
Completed Question:
Calculate the number of gold atoms in a 70g sample of gold(III) chloride . Be sure your answer has a unit symbol if necessary, and round it to significant digits
Explanation:
Given:
Molar mass of Au2cl6 = 303.33g/mol
Mass of Au2cl6 = 70g
Number of moles of Au2cl6 = 70g/303.33g/mol = 0.231mol
According to the chemical formula of Au2cl6,
1 mole of Au2cl6 contains 2 moles of Au
Number of moles of Au = 2 × 0.231mol = 0.462mole
There are 6.022 × 10^23 atoms in 1 mole of an element.
Number of Atom of gold in 0.462 mole of gold is:
N = 0.462 mol × 6.022 × 10^23 atoms/mol
N = 2.78 × 10^23 atoms
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Answer: Some signs of a chemical change are a change in color and the formation of bubbles. The five conditions of chemical change: color chage, formation of a precipitate, formation of a gas, odor change, temperature change.
Answer:
Proton is a sub atomic particle while oxygen is an atom ....
There are 2 electrons in the overlapping region.
Chlorine is the second member of the halogen group which are form of family of elements that resemble one another very closely.
The electronic configuration of chlorine shows the arrangement of chlorine electrons within it's atom.
At the outer most shell of the atom is seven electrons, therefore requires only one electron each to attain the octet arrangement.
The overlapping of the orbitals indicates the chemical bond formed by sharing of electrons between atoms called covalent bonding.
To complete it's outer most shell, it will need to share electron with another chlorine atom.
Therefore, there are 2 electrons in the overlapping region.
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