Answer:
980,100
Explanation:
let the recessive condition (aa) be represented as q² which is the genotypic frequency = 100/1,000,000 = 0.0001
allelic frequency of a = q = √q² = √0.0001 = 0.01. thus q = 0.01
From the formula p + q = 1 where p is the allelic frequency of A.
since q = 0.01
p = 1 - 0.01 = 0.99. The allelic frequency of A (p) = 0.99
p² = 0.99² = 0.9801. Genotypic frequency of AA= 0.9801
= 0.9801 x 1,000,000 = 980,100 individuals with AA (homozygous normal)
For 2pq genotypic frequency for hetrozygous (Aa).
Using the formula p² + 2pq + q² = 1. Since p² = 0.9801 and q² = 0.0001
2pq = 1 - (p² + q²)
= 1 - (0.9801 + 0.0001)
= 1 - (0.9802)
= 0.0198 = 0.0198 x 1,000,000 = 19,800 individuals with Aa
Answer:
The answer is most definietly ocean water due to the amount of salt loca
ted in the ocean.
Explanation:
Answer:
The correct answer is option D.
Explanation:
Thermohaline circulation is the circulation of currents in the deep ocean due to the density of the water which is controlled by heat and salinity. Water in the ocean posses layers or defined boundaries based on the density which provides driving force to the deep ocean currents.
Formation of these layers is due to the sinking of the cold water in the basin which and ice formation which leaves the salt in the seawater ,therefore, increasing salinity. This increased salinity increases its density and the surface water is replaced by the sinking water causing deep ocean currents.
Thus, option D is the correct answer.
Answer:
D. All of the above
Explanation:
Enzymes are proteins, act as biological catalysts, and are sensitive to factors like pH and temperature.
Hope this helps!
