The time period of the pendulum is affected by the acceleration due to gravity. The tension does not have any effect on the time period of the pendulum and also the mass of the bob does not effect the time period of the pendulum.
Hence, if the gravity increases then the time period of the pendulum will decreases and it will swing faster.
Answer:
USE SOCRACTIC IT WOULD REALLY HELP
The change in the internal energy of the ideal gas is determined as -28 J.
<h3>
Work done on the gas</h3>
The work done on the ideal gas is calculated as follows;
w = -PΔV
w = -1.5 x 10⁵(0.0006 - 0.0002)
w = -60 J
<h3>Change in the internal energy of the gas</h3>
ΔU = w + q
ΔU = -60J + 32 J
ΔU = -28 J
Thus, the change in the internal energy of the ideal gas is determined as -28 J.
Learn more about internal energy here: brainly.com/question/23876012
#SPJ1
*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆
Answer: Something that's vibrating, and you also need medium for those vibrations to start in.
I hope this helped!
<!> Brainliest is appreciated! <!>
- Zack Slocum
*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆
The spring is initially stretched, and the mass released from rest (v=0). The next time the speed becomes zero again is when the spring is fully compressed, and the mass is on the opposite side of the spring with respect to its equilibrium position, after a time t=0.100 s. This corresponds to half oscillation of the system. Therefore, the period of a full oscillation of the system is
Which means that the frequency is
and the angular frequency is
In a spring-mass system, the maximum velocity of the object is given by
where A is the amplitude of the oscillation. In our problem, the amplitude of the motion corresponds to the initial displacement of the object (A=0.500 m), therefore the maximum velocity is