Answer:
16.67% increase
Step-by-step explanation:
finding the percentage price increase
we need to find the difference in percentage price between the 2 years
12%-10% = 2%
2%/12% x 100% = 100%/6 = 16.67%
20% increase between January 1st 2010 and January 1st 2011
Answer:
95% confidence interval for the proportion of students supporting the fee increase is [0.767, 0.815]. Option C
Step-by-step explanation:
The confidence interval for a proportion is given as [p +/- margin of error (E)]
p is sample proportion = 870/1,100 = 0.791
n is sample size = 1,100
confidence level (C) = 95% = 0.95
significance level = 1 - C = 1 - 0.95 = 0.05 = 5%
critical value (z) at 5% significance level is 1.96.
E = z × sqrt[p(1-p) ÷ n] = 1.96 × sqrt[0.791(1-0.791) ÷ 1,100] = 1.96 × 0.0123 = 0.024
Lower limit of proportion = p - E = 0.791 - 0.024 = 0.767
Upper limit of proportion = p + E = 0.791 + 0.024 = 0.815
95% confidence interval for the proportion of students supporting the fee increase is between a lower limit of 0.767 and an upper limit of 0.815.
<span>6x^2+30x-36
= 6 (</span><span>x^2 + 5x - 6)
= 6 (x - 1)(x + 6)
hope it helps</span>
Area of a square = L * L
As you know 17 * 17 = 289
So length of one side of square equals 17