Answer: a=4, b=-8, c=-3
Step-by-step explanation: This equation isn't in standard form. To get it there, subtract -3 from both sides. This gets you an equation of 4x^2-8x-3.
The standard form is ax^2+bx+c.
A is the number before x^2 (4). B is the number before x, and since it's subtracted it's negative (-8). C is the last number, and since it's subtracted it's negative (-3).
Here are a few things you'll need to know for this question:
- Domain: <u>The list of x-values that are possible on a line.</u>
- Range: <u>The list of y-values that are possible on a line.</u>
- Interval Notation: <u>Shows the domain/range using the endpoints</u>. Brackets mean that the endpoint is included, parentheses mean the endpoint is excluded. Ex: (2,10]. 2 is excluded, 10 is included.
- Closed Circles: <u>The endpoint is included.</u>
- Open Circles: <u>The endpoint is excluded.</u>
So firstly, let's look at the domain. We see that there is a closed circle at x = -2 and an open circle at x = 5. Using what we know, <u>the interval notation of the domain is [-2,5).</u>
Next, let's look at the range. We see that there is a closed circle at y = -5 and an open circle at y = 2. Using what we know, <u>the interval notation of the range is [-5,2).</u>
The answer is 15*ln(m)-6*ln(n)
Hello!
To find the y-intercept of any given equation, you will need to substitute x for zero.
Also, to write the y-intercept as an ordered pair, it will look like (0, y), where y is the y-intercept, and x-value is zero because we substituted zero into all the x-values of the equation.
y = -(2^x) (substitute x = 0)
y = -(2^0) (any exponent raised to the power of zero is equal to one)
y = -(1) (simplify)
y = -1
Therefore, the y-intercept of the function y, is (0, -1).
Just plug in the x-values into the given equation to find. For 9-19-19 whatever the number is correlated to how much the graph is being moved down or up and the x is your slope.
