Answer:
F₁ / F₂ = 10
therefore the first out is 10 times greater than the second barrier
Explanation:
For this exercise let's use the relationship between momentum and momentum.
I = F t = Δp
in this case the final velocity is zero
F t = 0 -m v₀
F = m v₀ / t
in order to answer the question we must assume that the two vehicles have the same mass and speed
concrete barrier
F₁ = -p₀ / 0.1
F₁ = - 10 p₀
barrier collapses
F₂ = -p₀ / 1
let's look for the relationship of the forces
F₁ / F₂ = 10
therefore the first out is 10 times greater than the second barrier
Answer:
250 N
433 N
Explanation:
N = Normal force by the surface of the inclined plane
W = Weight of the block = 500 N
f = static frictional force acting on the block
Parallel to incline, force equation is given as
f = W Sin30
f = (500) Sin30
f = 250 N
Perpendicular to incline force equation is given
N = W Cos30
N = (500) Cos30
N = 433 N
Answer:
The cat will have <span>36J</span> of kinetic energy.
Answer:
25
Explanation:
Given:
1 can of concentrate requires 3 cans of water
Now,
Total ounces in 200 6-ounce cans = 1200 ounces
also,
for 1 can of concentrate requires 3 cans of water
thus,
for 12 ounces can water can required = 3 × 12 ounces = 36 ounces of cans
Thus,
total ounce of juice per can = 12 + 36 = 48 ounces per can
therefore,
the number of 12-ounce cans required are =
or
=
or
the number of 12-ounce cans required are = 25