Answer:
21 meters
Step-by-step explanation:
First find the circumference of the tire:
c = πd
c = 3.14(670)
c = 2103.8
Multiply by 10 to find the distance the bike has travelled:
2103.8*10 = 21,038
Convert millimeters to meters:
21,038 millimeters ≈ 21 meters
The square feet of landscaping will the two companies carry out that enables them to charge the same amount is 30
What is the total of the landscaping contract for each company?
The total cost of the landscaping contract for each of the two companies is the sum of the fixed consulting fee plus the multiple of variable charge per square foot multiplied by the number of square feet of landscaping
Company A:
Total cost=300+7S
S=square foot
Company B:
Total cost=120+13S
At the point where the square foot are the same they charge the same amount
300+7S=120+13S
300-120=13S-7S
180=6S
S=180/6
S=30 square foot
Find out more about total cost on: brainly.com/question/15686427
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<u>ANSWER</u>
The line that is parallel to 
through 
is 
.
<u>EXPLANATION</u>
The equation that is parallel to the line has a slope that is equal to the slope of this line.
By comparing this equation to the general slope intercept form,
,this line has slope 
.
Hence the line parallel to this line also has slope .
Let 
be the equation of the line parallel to the line
We can substitute to obtain;
If the line passes through the point ,then this point must satisfy its equation.
We substitute 
and 
to obtain;
We this equation for 
.
We substitute this value of 
in to to get;
.
Hence the equation of the line that is parallel to through is .
Part (a)
<h3>Answer: 0</h3>
-------------------
Explanation:
Point P is part of 3 planes or faces of this triangular prism:
- plane PEF (the front slanted plane)
- plane PEH (the left triangular face)
- plane PHG (the back rectangular wall)
Notice how each three letter sequence involves "P", though this isn't technically always necessary. I did so to emphasize how point P is involved with these planes.
Each of the three planes mentioned do not involve line FG
- Plane PEF only deals with point F
- Plane PEH doesn't have any of F or G involved
- plane PHG only involves G
So there are no planes that contain line FG and point P.
==================================================
Part (b)
<h3>Answer: 0</h3>
-------------------
Explanation:
It's the same idea as part (a) earlier. The planes involving point G are
- plane GQF (triangular face on the right)
- plane GFE (bottom rectangular floor)
- plane GHP (back rectangular wall)
None of these planes have line EP going through them.
As an alternative, we could reverse things and focus on all of the planes connected to line EP. Those 2 planes are
- plane PEH (triangular face on the left)
- plane PEF (front slanted rectangular face)
None of these planes have point G located in them.
