Answer:
The pH is 13,00 and the solution is basic.
Explanation:
<em> </em>The pH indicates the acidity or basicity of a substance. PH values between 0 and less than 7 indicate acidic solutions, 7 neutral and higher than 7 to 14 basic. It is calculated as
pH = -log (H 30+)
Both pH and pOH have a relationship to belonging to the same aqueous solution: the expression of the Kwater (ionic product of the water Kw) is used:
[H3O ^ +]x [OH ^ -] = 1x 10 ^ -14
[H3O ^ +]x [1.0 10-1]=1x 10 ^ -14
[H3O ^ +]= 1x 10 ^ -14/1.0 10-1M= <em>1.0 10-13 M</em>
pH = -log (H 30+)= -log (1.0 10-13 M)= <em>13, 00</em>
As the pH value is higher than 7, it corresponds to a basic substance.
Answer:
(a): 2ZnO(s) -----------> 2Zn(s) + O2(g)
2C(s) + O2(g) ---------> 2CO(g)
(b): ZnO(s) + C(s) ---------> Zn(s) + CO(g)
Answer:
The pressure, when the volume is reduced to 7.88L, is 846 torr (option A)
Explanation:
Step 1: Data given
The temperature of a gas = 25.0°C
AT 25 °C the gas occupies a volume of 10.0L and a pressure of 667 torr.
The volume reduces to 7.88 L but the temperature stays constant.
Step 2: Boyle's law
(P1*V1)/T1 = (P2*V2)/T2
⇒ Since the temperature stays constant, we can simplify to:
P1*V1 = P2*V2
⇒ with P1 = the initial pressure 667 torr
⇒ with V1 = the initial volume = 10.0 L
⇒ with P2 = the final pressure = TO BE DETERMINED
⇒ with V2 = the final volume = 7.88L
P2 = (P1*V1)/V2
P2 = (667*10.0)/7.88
P2 = 846 torr
The pressure, when the volume is reduced to 7.88L, is 846 torr (option A)
Answer:
5.83 mol.
Explanation:
- From the balanced reaction:
<em>2Al + 3Ag₂S → 6Ag + Al₂S₃,</em>
It is clear that 2 mol of Al react with 3 mol of Ag₂S to produce 1 mol of Ag and 1 mol of Al₂S₃.
Al reacts with Ag₂S with (2: 3) molar ratio.
<em>So, 2.27 mol of Al reacts completely with 3.4 mol of Ag₂S with (2: 3) molar ratio.</em>
<em />
- The limiting reactant is Ag₂S.
- The excess "left over" reactant is Al.
The reamining moles of excess reactant "Al" = 8.1 mol - 2.27 mol = 5.83 mol.
I don't know if this is the answer you are looking for but it would be flat unless the player pushed the tuning slide in.