You subtract the number (5) on the other side of the = sign from the number on the side of the = sign. and divide (-5a) by the number you subtracted before. So untimely- 5-5= 0 ÷ -5a = 0
Answer:
and .
Step-by-step explanation:
So I believe the problem is this:
where we are asked to find values for and such that the equation holds for any in the equation's domain.
So I'm actually going to get rid of any domain restrictions by multiplying both sides by (x-3)(x+7).
In other words this will clear the fractions.
As you can see there was some cancellation.
I'm going to plug in -7 for x because x+7 becomes 0 then.
Divide both sides by -10:
Now we have:
with
I notice that x-3 is 0 when x=3. So I'm going to replace x with 3.
Divide both sides by 10:
So and .
Answer:
see below
Step-by-step explanation:
A. Reflection across the y-axis replaces each x coordinate with its opposite.
B. Rotation 90° CW does the transformation (x, y) ⇒ (y, -x)
C. This is a translation left 2 units.
D. Rotation 90° CCW does the transformation (x, y) ⇒ (-y, x)
E. This is a translation left 7 and down 2.
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In the attached graphs, we have identified a point that is a corresponding point on each figure. This is so you can see how the various transformations move it and the rest of the figure in relation to it. 90° arcs are shown so you can see the rotations more easily.
The figures are labeled and color coded in accordance with the problem statement.