The weights of a large number of miniature poodles are approximately normally distributed with a mean of 8 kilograms and a stand
ard deviation of 0.9 kilogram. If measurements are recorded to the nearest tenth of a kilogram, find the fraction of these poodles with weights
1 answer:
Answer and Step-by-step explanation:
Considering the table attached.
(a) over 9.5 kg;
μ = 8
σ = 0.9
z = 9.5 - 8/0.9 ≈ 1.67
P (Z > 1.67) = 0.5 - P(0<Z<1.67) = 0.5 - 0.4525 = 0.0475
(b) at most 8.6 kg;
z = 8.6-8/0.9 ≈ 0.67
P(Z < 0.67) = 0.5 + P(0<Z<0.67) = 0.5 + 0.2486 = 0.7486
(c) between 7.3 and 9.1 kg.
z₁ = 7.3-8/0.9 ≈ -0.78
z₂ = 9.1 - 8/0.9 ≈ 1.22
P(-0.78 < Z < 1.22) = P(0 < Z < 0.78) + P(0 < Z < 1.22) = 0.2823 + 0.3888 = 0.6711
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4p=-12---- > p=-12/4
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</span>the answer is (-3,0)
y²=-12x
the vertex is the point (0,0)------------- > see the attached figure
<span>
standard form: (y-k)^2=4p(x-h), with (h,k) being the (x,y) coordinates of the vertex.
vertex(0,0)
4p=-12---- > p=-12/4
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Focus:(-3,0)
</span>the answer is (-3,0)