The molar extinction coefficient is 15,200 
.
The formula to be used to calculate molar extinction coefficient is -
A = ξcl, where A represents absorption, ξ refers molar extinction coefficient, c refers to concentration and l represents length.
The given values are in required units, hence, there is no need to convert them. Directly keeping the values in formula to find the value of molar extinction coefficient.
Rewriting the formula as per molar extinction coefficient -
ξ = 
ξ = 
Performing multiplication in denominator to find the value of molar extinction coefficient
ξ = 
Performing division to find the value of molar extinction coefficient
ξ = 15,200
Hence, the molar extinction coefficient is 15,200 .
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Volume= Mass/ Density= 20/184
= 0.108 cubic cm
Answer:
0.83 mL
Explanation:
Given data
- Initial concentration (C₁): 12 M
- Final concentration (C₂): 1.0 M
- Final volume (V₂): 10.0 mL
We can calculate the initial volume of HCl using the dilution rule.
C₁ × V₁ = C₂ × V₂
V₁ = C₂ × V₂ / C₁
V₁ = 1.0 M × 10.0 mL / 12 M
V₁ = 0.83 mL
The required volume of the initial solution is 0.83 mL.
Answer:
6 oxygen atoms
Explanation:
Step 1: Given data
Number of dinitrogen monoxide molecules (N₂O): 6
Number of oxygen atoms (O): ?
Step 2: Calculate the appropriate ratio
The ratio of dinitrogen monoxide molecules to oxygen atoms is 1:1.
Step 3: Use the ratio to calculate the number of oxygen atoms
6 molecule N₂O × (1 atom O/1 molecule N₂O): 6 atom O
Answer: C(s) + O2(g) --> CO2(g)12g (C) .... 50.8g (O2)................. initial amounts0g(C) .........18.8g(O2) ................. amounts when reaction completeThat means that C was the limiting reactant, and the amount of CO2 is based on the amount of carbon that burned. Covert 12 grams of carbon to moles. The moles of CO2 will be the same, since they are in a 1:1 mole ratio. Then convert the moles of CO2 to grams.12g C x (1 mol C / 12.0 g C) x (1 mol CO2 / 1 mol C) x (44.0g CO2 / 1 mol CO2) =44 g of CO2
