1 point
Find mzJKL.
(3x + 15) (2x + 10)°
J
K
M
2 answers:
Answer:
∠JKL = 108°
Step-by-step explanation:
1.) Add 3x + 15 and 2x + 10 for 180
→ (3x + 15) + (2x + 10) = 180
2.) Add common factors
→ 5x + 25 = 180
3.) Solve for x
→ x = 31
4.) Replace x with 31
→ 3(31) + 15 = 108
∠JKL = 108°
TO CHECK
1.) Replace x with 31
→ 2(31) + 10
2.) Add 108 and 72 to get 180
→ 108 + 72 = 180
Answer:
m<jkl =0
Step-by-step explanation:
step 1: keep it ir mind that angle jkl and angle lkm are equal
step 2: since they are equal thus:
m<jkl= m<lkm
3x + 15= 2x + 10
3x-2x= 10-15
x = -5
Step 3: substitute x= -5 in m<jkl
3(-5)+15
-15+15 = 0
therefore your answer for both anhle should be 0
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Y> or equal 82P/100
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