Answer:
Surface area of cube =6× l^2 (where l is the side of cube)
Therefire 6×9^2=6×81
=486in^2
These are two questions and two answers:
Question 1:
<span>A
quadratic equation is shown below: 3x^2 − 15x + 20 = 0 Part A: Describe
the solution(s) to the equation by just determining the radicand. Show
your work.
Answer: </span><span>The negative value of the radicand means that the equation does not have real solutions.
Explanation:
1) With radicand the statement means the disciminant of the quadratic function.
2) The discriminant is: b² - 4ac, where a, b, and c are the coefficients of the quadratic equation: ax² + bx + c
3) Then, for 3x² - 15x + 20, a = 3, b = - 15, and c = 20
and the discriminant (radicand) is: (-15)² - 4(3)(20) = 225 - 240 = - 15.
4) The negative value of the radicand means that the equation does not have real solutions.
Question 2:
Part B: Solve 3x^2 + 5x − 8 = 0 by using an appropriate
method. Show the steps of your work, and explain why you chose the
method used.
Answer: </span> two solutions x = 1 and x = - 8/3x
Explanation:
1) I choose factoring (you may use the quadratic formula if you prefer)
2) Factoring
Given: 3x² + 5x − 8 = 0
Make 5x = 8x - 3x: 3x² + 8x - 3x - 8 = 0
Group: (3x² - 3x) + (8x - 8) = 0
Common factors for each group: 3x(x -1) + 8(x - 1) = 0
Coomon factor x - 1: (x - 1) (3x + 8) = 0
The two solutions are for each factor equal to zero:
x - 1 = 0 ⇒ x = 1
3x + 8 = 0 ⇒ x = -8/3
Those are the two solutions. x = 1 and x = - 8/3
Answer:
-.095
Step-by-step explanation:
Answer: $3.42
Step-by-step explanation:
Interest= Principal x Rate x Time
From the question, Principal =$2,150
Rate= 22.9% annually means per year, to calculate the monthly rate, we divide by 12
=22.9%/12 = 1.908% per month
Time = one month, meaning one month out of 12months = 1/12
I is therefore: 2150 x 1.908% x 1/12
= 2150 × 0.01908 x 0.0833
=$3.42
I hope this is clear, please mark as brainliest answer.
Answer:
Step-by-step explanation:
Given
Required
Find r
From the question, we understand that G is a point between D and M:
This implies that:
Substitute values for DM, DG and GM
Collect Like Terms
Solve for r
