Answer:
61.712
Step-by-step explanation:
Multiply .8x.04
Multiply .8x.0
Multiply .8x2
Multiply .8x2
Than add a zero under the answer of .8x.04
Multiply 2x.04
Multiply 2x.0
Multiply 2x2
Multiply 2x 2
Answer:
Actually, what you said you have so far is not correct. The 2 correct answers are the 1st one (x + y = 15) and the 5th one (15x + 10y > 180)
Step-by-step explanation:
If tutoring French is x hours and scooping ice cream is y hours and he is going to work 15 hours for sure doing both, then we can add them together to get that x hours + y hours = 15 hours, or put simply: x + y = 15.
Now we are going to throw in the added fun of the money he makes doing each. The thing to realize here is that we can only add like terms. So looking at the equation above, we have x hours of tutoring and y hours of scooping, so if we want to add them, we will add those number of hours together to get the total number of hours he worked, which we know to be 15. The same goes for money. If we add money earned from tutoring to money earned from scooping, we need that to be greater than the money he wants to earn which is 180 at least. Because he wants to earn MORE than $180. we use the ">" sign. Since he earns $15 an hour tutoring, that expression is $15x; since he earns $10 an hour scooping, that expression is $10y. Now add them together (and you CAN because they are both expressions relating dollars to dollars) and set the sum > $180:
$15x + $10y > $180. That's why your answer is not correct. Use mine (with the understanding that you care about why yours is wrong and mine is correct) and you'll be fine.
The total measure of the interior angles of each figure will be:
180 (n-2) = 180 (4 - 2) = 360
Now add all those angles and set them equal to 360.
41 + 133 + 86 + x = 360
x is the unknown angle.
260 + x = 360
x = 100
The missing angle that is Not labeled in any of the figure is 100°
Hope this helps :)
That one looks very difficuly
Answer:
The exponent is 2.
Step-by-step explanation:
Remember multiplicity rules:
- If a factor has an odd multiplicity (e.g. it is raised to 1, 3, 5...) then it will cross the x-axis.
- If a factor has an even multiplicity (e.g. it is raised to 2, 4, 6...) then it will bounce off the x-axis.
At x=2, we have the factor (x-2).
From the graph, we can see that the graph bounces off at that point.
Hence, the multiplicity of (x-2) must be even.
Therefore, a possible exponent for the factor (x-2) is 2. Any even number will suffice.