All categories

2 years ago

Use the chart to multiply the binomial by the trinomial. Which polynomial is the correct product?

Mathematics

2 answers:

Alex777 [14]2 years ago

4 0

Answer: $6y^3 + 17y^2 + 22y + 15$

Step-by-step explanation:

Here, the given expression, $(2y+3). (3y^2+4y+5)$

By applying distribution property in second bracket,

= $3y^2(2y+3)+4y(2y+3)+5(2y+3)$

= $6y^3+9y^2+8y^2 +12y+10y+15$ ( again by applying distributive property)

= $6y^3+17y^2 +22y+15$ ( by adding like terms)

Thus, $(2y+3). (3y^2+4y+5)$ = $6y^3+17y^2 +22y+15$

oksano4ka [1.4K]2 years ago

3 0

The awnser is :
6y^3 + 17y^2 + 22y + 15
Hope it helps

You might be interested in

This one as well, does anyone know the answer?

Mashutka [201]

D is the answer to the question

5 0

2 years ago

Tammy says the quotient of 793 ÷ 6 is 132 r1. Use multiplication to check Tammy's answer. × 6 + 1 = Tammy's answer is .

Troyanec [42]

To find the answer, we should multiply 132 by 6.

132*6=792

792+1=793

Tammy’s answer is correct.

7 0

2 years ago

I 4 (4, 3)) 2 4 x (1, -1) The slope is positive v Find the slope.

Cloud [144]

Answer:

the slope is 4/3

Step-by-step explanation:

so the equation of your problem would be y=4/3x-2

-2 is your y-intercept (or your b)

pls vote brainliest tyyy <3

4 0

2 years ago

2(x + 3)=x - 4 help me

Irina18 [472]

Answer:

x = -10

Step-by-step explanation:

2(x+3) = x-4 --> multiply (x+2) times 2

2x+6 = x - 4 --> subtract x from both sides

x+6 = -4 --> subtract 6 from both sides

x = -10

4 0

2 years ago

Read 2 more answers

Consider F and C below. F(x, y, z) = yz i + xz j + (xy + 6z) k C is the line segment from (2, 0, −2) to (5, 4, 2) (a) Find a fun

WITCHER [35]

Answer:

Required solution (a) $f(x,y,z)=xyz+3z^2+C$ (b) 40.

Step-by-step explanation:

Given,

$F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k$

(a) Let,

$F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k=f_x \uvec{i} +f_y \uvex{j}+f_z\uvec{k}$

Then,

$f_x=yz,f_y=xz,f_z=xy+6z$

Integrating $f_x$ we get,

$f(x,y,z)=xyz+g(y,z)$

Differentiate this with respect to y we get,

$f_y=xz+g'(y,z)$

compairinfg with $f_y=xz$ of the given function we get,

$g'(y,z)=0\implies g(y,z)=0+h(z)\implies g(y,z)=h(z)$

Then,

$f(x,y,z)=xyz+h(z)$

Again differentiate with respect to z we get,

$f_z=xy+h'(z)=xy+6z$

on compairing we get,

$h'(z)=6z\implies h(z)=3z^2+C$ (By integrating h'(z)) where C is integration constant. Hence,

$f(x,y,z)=xyz+3z^2+C$

(b) Next, to find the itegration,

$\int_C \vec{F}.dr=\int_C \nabla f. d\vec{r}=f(5,4,2)-f(2,0,-2)=(52+C)-(12+C)=40$

3 0

2 years ago