Answer:
I assume you know Arithmetic Progression .
so, we have to find the first and last 4-digit number divisible by 5
first = 1000 , last = 9990
we have a formula, 
= a + (n-1)d
here, is the last 4-digit number divisible by 5.
n is the number of 4-digit even numbers divisible by 5
d is the common difference between the numbers, which is 10 in this case
a is the first 4-digit number divisible by 5
9990 = 1000 + (n-1)*10
899 = n-1
n = 900
Hence, there are 900 4-digit even numbers divisible by 5
Answer:
The number is 5
Step-by-step explanation:
If we need to find the hidden number, Which for simplicity's sake we will denote as "n", lets first write out the equation.
"2 x [n + (-3)] = 4"
We can work through this problem backwards. if we need two times the sum of "n" and (-3) to get to 4, the only number that can be multiplied by 2 to get a product of 4 is 2, so "n" + (-3) must equal 2. so, From here, we can figure out that since 5 + (-3) equals 2, "n" Must equal 5. so, if we plug in 5 for "n" the equation looks like this:
"2 x [5 + (-3)] = 4"
So, since the equation makes sense, the answer is, "n = 5"
Answer:
-1
Step-by-step explanation:
To simplify 3a + 2b - 8a + b, we need to combine like terms. Like terms are terms that share common variables. In this expression, the two variables are terms with a and terms with b. The terms that have a are 3a and -8a. The terms that have b are 2b and b. Now we can separate them and simplify.
(3a - 8a) + (2b + b)
-5a + 3b
$45+$18+$26-$21-$93
45+18=63
63+18=81
81+26=107
107-21=86
86-93=-7
