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2 years ago

-22+4(6x-1)+5 how do I simply by combing like terms

Mathematics

1 answer:

irinina [24]2 years ago

5 0

Answer:

24x-21

Step-by-step explanation:

First, you have to use distributive property.

-22+24x-4+5

To combine like terms, you have to notice the constants and put them together.

-21+24x

You must know that numbers with variables have to go first.

24x-21

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Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.

Troyanec [42]

Answer: 300

Step-by-step explanation:

Let the number be represented by x.

Therefore, based on the information given in the question, this can be expressed as:

36% of x = 108

36/100 × x = 108

0.36 × x = 108

0.36x = 108

x = 108/0.36

x = 300

Therefore, the number is 300

8 0

2 years ago

On Earth, objects weigh 6 times what

Colt1911 [192]

Answer:

16 pounds.

Step-by-step explanation:

As you said, objects weigh 6 times more than what they weigh on the moon. Therefore, the robot originally weighing 96 pounds will be reduced to 16 pounds.

16*6=96. (Original Weight)

96/6=16. (Weight after being on the moon.)

4 0

2 years ago

What would x equal for the missing side

OverLord2011 [107]

X = 12

18/24 = .75
16 x .75 = 12

5 0

2 years ago

An automobile manufacturer would like to know what proportion of its customers are not satisfied with the service provided by th

butalik [34]

Answer:

a) A sample size of 5615 is needed.

b) 0.012

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

99.5% confidence level

So $\alpha = 0.005$ , z is the value of Z that has a pvalue of $1 - \frac{0.005}{2} = 0.9975$ , so $Z = 2.81$ .

(a) Past studies suggest that this proportion will be about 0.2. Find the sample size needed if the margin of the error of the confidence interval is to be about 0.015.

This is n for which M = 0.015.

We have that $\pi = 0.2$

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.015 = 2.81\sqrt{\frac{0.2*0.8}{n}}$

$0.015\sqrt{n} = 2.81\sqrt{0.2*0.8}$

$\sqrt{n} = \frac{2.81\sqrt{0.2*0.8}}{0.015}$

$(\sqrt{n})^{2} = (\frac{2.81\sqrt{0.2*0.8}}{0.015})^{2}$

$n = 5615$

A sample size of 5615 is needed.

(b) Using the sample size above, when the sample is actually contacted, 12% of the sample say they are not satisfied. What is the margin of the error of the confidence interval?

Now $\pi = 0.12, n = 5615$ .