Not an expertise on infinite sums but the most straightforward explanation is that infinity isn't a number.
Let's see if there are anything we missed:
∞
Σ 2^n=1+2+4+8+16+...
n=0
We multiply (2-1) on both sides:
∞
(2-1) Σ 2^n=(2-1)1+2+4+8+16+...
n=0
And we expand;
∞
Σ 2^n=(2+4+8+16+32+...)-(1+2+4+8+16+...)
n=0
But now, imagine that the expression 1+2+4+8+16+... have the last term of 2^n, where n is infinity, then the expression of 2+4+8+16+32+... must have the last term of 2(2^n), then if we cancel out the term, we are still missing one more term to write:
∞
Σ 2^n=-1+2(2^n)
n=0
If n is infinity, then 2^n must also be infinity. So technically, this goes back to infinity.
Although we set a finite term for both expressions, the further we list the terms, they will sooner or later approach infinity.
Yep, this shows how weird the infinity sign is.
Answer:
<u>158666666666666667</u>
1
Step-by-step explanation:
You move the decimal point two (2) places to the left to get a whole number and you put it over one because they did not give you the denominator so that is why you put it over one.
Answer:
Step-by-step explanation:
We can write an relationship for this as:
3
:
2
→
24
:
b
Where
b
is the number of burgers sold without cheese.
We can rewrite the relationship as an equation and solve for
b
:
3
2
=
24
b
2
3
=
b
24
24
×
2
3
=
24
×
b
24
48
3
=
24
×
b
24
16
=
b
b
=
16
The restaurant would of sold
16
burgers without cheese with the information provided in the problem.
Check the picture below.
you really have two rectangles, a 6x10 and a 6x5, and surely you know what those areas are, so sum them up, and that's the area of the polygon.
