Answer: w = -3u/2 + 2
Step-by-step explanation:
-12u + 13 = 8w - 3
-12u + 13 + 3 = 8w -3 + 3
-12u + 16 = 8w
w = -3u/2 + 2
Answer:
x =
Step-by-step explanation:
Given
- = ← factor denominator
- =
[ x ≠ 0, x ≠ - 1 as these would make the terms undefined ]
Multiply through by x(x + 1)
4x² - 5(x + 1) = 4
4x² - 5x - 4 = 4 ( subtract 4 from both sides )
4x² - 5x - 9 = 0 ← in standard form
(x + 1)(4x - 9) = 0 ← in factored form
Equate each factor to zero and solve for x
x + 1 = 0 ⇒ x = - 1
4x - 9 = 0 ⇒ 4x = 9 ⇒ x =
However, x ≠ - 1 for reason given above, then
solution is x =
Answer:
3/8
Step-by-step explanation:
1 - 1/4 = 3/4
1/2 of 3/4 = 3/8
Annually The amount after 10 years = $ 7247.295
quarterly compound after 10 years = $7393.5
Continuously interest =$7,419
Given:
P = the principal amount
r = rate of interest
t = time in years
n = number of times the amount is compounding.
Principal = $4500
time= 10 year
Rate = 5%
To find: The amount after 10 years.
The principal amount is, P = $4500
The rate of interest is, r = 5% =5/100 = 0.05.
The time in years is, t = 10.
Using the quarterly compound interest formula:
A = P (1 + r / 4)4 t
A= 4500(1+.05/4)40
A= 4500(4.05/4)40
A= 4500(1.643)
Answer: The amount after 10 years = $7393.5
Using the Annually compound interest formula:
A = P (1 + r / 100) t
A= 4500(1+5/100)10
A= 4500(105/100)10
Answer: The amount after 10 years = $ 7247.295
Using the Continuously compound interest formula:
e stands for Napier’s number, which is approximately 2.7183
A= $2,919
Answer: The amount after 10 years = $4500+$2,919=$7,419
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Step-by-step explanation:
Vamos simplificar passo a passo.
k2-6k4-(3k4+k2+2)
Distribua o sinal negativo:
=k2-6k4+-1(3k4+k2+2)
=k2+-6k4+-1(3k4)+-1k2+(-1)(2)
=k2+-6k4+-3k4+-k2+-2
Combine os termos semelhantes:
=k2+-6k4+-3k4+-k2+-2
=(-6k4+-3k4)+(k2+-k2)+(-2)
=-9k4+-2
Responda:
=-9k4-2