Answer:
According to the hormone diagram of the menstrual cycle, the woman is not pregnant due to the behavior of progesterone and estrogens, whose levels do not increase, in addition to the absence of human chorionic gonadotropin.
Explanation:
The graph shows the behavior of hormones during a woman's menstrual cycle in the absence of pregnancy.
During a woman's normal cycle, estrogen, luteinizing hormone (LH) and follicle stimulating hormone (FSH) tend to increase prior to ovulation, reach their peak values at ovulation, and then decline, as shown in the graph. Progesterone, on the other hand, increases after ovulation and decreases if the woman does not become pregnant.
In the case of a pregnant woman:
- <u>Estrogens</u> continue to increase after ovulation, produced by the ovaries and placenta.
- <u>Progesterone</u> also increases its levels, as it is a hormone produced by the ovaries and placenta.
- <u>Hormone human chorionic gonadotropin</u> (HCG) appears and increases during pregnancy, due to the secretory activity of the placenta.
<em><u>The diagram represents the normal cycle of a woman who is not pregnant</u></em>.
Answer:
Phenotype genotype Number of individuals
Red RR 245
Pink Rr 210
White rr 45
Number of alleles in total
R = 245 + 245 + 210 = 700 ---> 700/1000= 0.7 R frequency
r = 210 + 45 + 45 = 300 -----> 300/1000 = 0.3 r frequency
Predict (Hardy Weinberg) genotype frequencies=
p^2 + 2pq + q^2 = 1
p= 0.7
q=0.3
0.49 + 0.42 + 0.9 =1
According Punnett Squares in F1 we have=
Rr* rr = Rr 50% and rr 50%
Answer:
Hello There!!
Explanation:
It is a specialised cellular part for example nucleus and mitochondria.
hope this helps,have a great day!!
~Pinky~
Correct Question:
An asynchronous counter signal:
Answer:
overrides the clock-gated input signal(s).
Explanation:
An asynchronous counter signal normally overrides the clock-gated input signal(s).
An asynchronous counter is a type of counter whereby each flip-flop output serves as the clock input signal for the next flip-flop signals and preset can be used to override the clock-gated input signal(s).
