Explanation:
(a) The given data is as follows.
Temperature (T) = = (25 + 273) K = 298 K
= 43000 J/mol
Since, both the liquid and vapors are at equilibrium. Therefore, change in free energy will be calculated as follows.
= 0
43000 - = 0
= -144 J/mol K
Negative sign indicates an increase in entropy of the system.
Now, for 1 mole of is as follows.
= 144 J/K
So, - 214 = 144 J/k
= 358 J/K
Therefore, we can conclude that entropy of vapor is 358 J/K.
(b) As we know that intensive variable are the variables which do not depend on the amount of a substance.
So, in the given situation only temperature will act as an intensive variable that will be required to completely specify the vapor-liquid mixture of .
Proton and Neutron numbers within an atom cannot change, however, the electron number may change and form an ion. The answer is True
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J.J. Thomson's cathode ray experiment was a set of three experiments that assisted in discovering electrons. He did this using a cathode ray tube or CRT. It is a vacuum sealed tube with a cathode and anode on one side.