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2 years ago

8

The waiter places a bowl of soup in front of Abbey. In a counterclockwise direction, she passes the soup to Kai who then passes

it to Haifa. Which two rotations about the center of the table describe passing the soup?

2 answers:

4vir4ik [10]2 years ago

8 0

First 60° and then 90°

melamori03 [73]2 years ago

5 0

first 60° and then 90°

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Kamal solved an equation as shown below. 3(x-8)=x+2x+7 3x-24=3x+7 -24=7 What is the solution to Kamal’s equation?

dem82 [27]

Answer:

7 is correct

Step-by-step explanation:

7 0

2 years ago

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The point (1/3,1/4) lies on the terminal said of an angle. Find the exact value of the six trig functions and explain which func

katrin2010 [14]

Answer:

sine and cosec are inverse of each other.

cosine and sec are inverse of each other.

tan and cot are inverse of each other.

Step-by-step explanation:

Given point on terminal side of an angle ( $\frac{1}{3},\frac{1}4$ ).

Kindly refer to the attached image for the diagram of the given point.

Let it be point A( $\frac{1}{3},\frac{1}4$ )

Let O be the origin i.e. (0,0)

Point B will be ( $\frac{1}{3},0$ )

Now, let us consider the right angled triangle $\triangle OBA$ :

Sides:

$Base, OB = \frac{1}{3}\\Perpendicular, AB = \frac{1}{4}$

Using Pythagorean theorem:

$\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow OA^{2} = OB^{2} + AB^{2}\\\Rightarrow OA^{2} = \frac{1}{3}^{2} + \frac{1}{4}^{2}\\\Rightarrow OA = \sqrt{\frac{1}{3}^{2} + \frac{1}{4}^{2}}\\\Rightarrow OA = \sqrt{\frac{4^2+3^2}{3^{2}.4^2 }}\\\Rightarrow OA = \frac{5}{12}$

$sin \angle AOB = \dfrac{Perpendicular}{Hypotenuse}$

$\Rightarrow sin \angle AOB = \dfrac{\frac{1}{4}}{\frac{5}{12}}\\\Rightarrow sin \angle AOB = \dfrac{3}{5}$

$cos\angle AOB = \dfrac{Base}{Hypotenuse}$

$\Rightarrow cos \angle AOB = \dfrac{\frac{1}{3}}{\frac{5}{12}}\\\Rightarrow cos\angle AOB = \dfrac{4}{5}$

$tan\angle AOB = \dfrac{Perpendicular}{Base}$

$\Rightarrow tan\angle AOB = \dfrac{3}{4}$

$cosec \angle AOB = \dfrac{Hypotenuse}{Perpendicular}$

$\Rightarrow cosec\angle AOB = \dfrac{5}{3}$

$sec\angle AOB = \dfrac{Hypotenuse}{Base}$

$\Rightarrow sec\angle AOB = \dfrac{5}{4}$

$cot\angle AOB = \dfrac{Base}{Perpendicular}$

$\Rightarrow cot\angle AOB = \dfrac{4}{3}$

3 0

2 years ago

F = 0.272727... <br> 100f = (100) (0.272727...) <br> 100f = ?

olya-2409 [2.1K]

100f = 27.272727.....

5 0

2 years ago

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A square pyramid is sliced so that the cross section is perpendicular to its base. The cross section intersects the vertex of th

Artist 52 [7]

<span>The cross section of the shape is a triangle.

So B.triangle should be your answer

Hoped this helped :D</span>

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2 years ago

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20) In a recent poll of 1200 randomly selected adult office workers, 32% said they had worn a Halloween costume to the office at

Allisa [31]

Answer: Option 'c' is correct.

Step-by-step explanation:

Since we have given that

n = 1200

x = 32% of 1200

So, $\hat{p}=32\5=0.32$

We need to find 95% confidence interval.

so, z = 1.96

So, margin of error would be

$z\times \sqrt{\dfrac{p(1-p)}{n}}\\\\=1.96\times \sqrt{\dfrac{0.32\times 0.68}{1200}}\\\\=1.96\times 0.0135=$

So, Interval would be

$\hat{p}\pm \text{margin of error}}\\\\=0.32\pm 0.0263\\\\=(0.32-0.0263,0.32+0.0263)\\\\=(0.2937,0.3463)\\\\=(0.294,0.346)\\\\=(29.4\%,34.6\%)$

Hence, Option 'c' is correct.

6 0

2 years ago