Answer:
Explanation:
Given:
Pressure = 745 mm Hg
Also, P (mm Hg) = P (atm) / 760
Pressure = 745 / 760 = 0.9803 atm
Temperature = 19 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (19 + 273.15) K = 292.15 K
Volume = 0.200 L
Using ideal gas equation as:
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 0.0821 L.atm/K.mol
Applying the equation as:
0.9803 atm × 0.200 L = n × 0.0821 L.atm/K.mol × 292.15 K
⇒n = 0.008174 moles
From the reaction shown below:-
1 mole of react with 2 moles of
0.008174 mole of react with 2*0.008174 moles of
Moles of = 0.016348 moles
Volume = 13.4 mL = 0.0134 L ( 1 mL = 0.001 L)
So,
1) when litmus paper is dipped into a acid solution, the litmus paper turns red.
<span>2) acid reacts with metals to produce hydrogen gas </span>
<span>3) the equation of an acidic substance begins with the letter 'H' such as HCl </span>
Answer:
to show that atoms are conserved in chemical reactions
Explanation:
The liquid that is been dispensed during titration as regards this question is Titrant.
- Titration can be regarded as common laboratory method that is been carried out during quantitative chemical analysis.
- This analysis helps to know the concentration of an identified analyte.
- Burette can be regarded as laboratory apparatus.
It is used in the in measurements of variable amounts of liquid ,this apparatus helps in dispensation of liquid, especially when performing titration.
- The specifications is been done base on their volume, or resolution.
- The liquid that comes out of this apparatus is regarded as Titrant, and this is gotten during titration process, which is usually carried out during volumetric analysis.
Therefore, burrete is used in volumetric analysis.
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Answer:
Explanation:
Molarity is a measure of concentration in moles per liter.
The molarity of the solution is 1.2 M NaNO₃ or 1.2 moles NaNO₃ per liter. There are 0.25 liters of the solution. The moles of solute are unknown, so we can use x.
- molarity= 1.2 mol NaNO₃/L
- liters of solution=0.25 L
- moles of solute =x
We are solving for x, so we must isolate the variable, x. It is being divided by 0.25 liters. The inverse of division is multiplication, so we multiply both sides by 0.25 L.
The units of liters cancel, so we are left with the units moles of sodium nitrate.
There are 0.3 moles of sodium nitrate.