The reaction is missing and it's ;
N2H4 + H2 ---> 2NH3
It asks for the total pressure too.
Answer:
A) Rate of change for NH3 = 152 torr/h
B) The total pressure in the vessel will remain the same.
Step-by-step explanation:
N2H4 + H2 ---> 2NH3
1 mole of N2H4 yields 2 moles of NH3.
From the question, the rate given for N2H4 is 76 torr/h.
Thus, The rate of change for NH3 will be = 2 x 76 = 152 torr/h
Now, on the reaction side, 1 mole of N2H4 reacts with 1 mole of H2. So we have 2 moles on the left hand side.
While on the product side, 2 moles of NH3 are produced.
So the total pressure will remain the same because for every 2 moles on the reaction side, 2 moles are gotten on the product side.
If you would like to know what is f(2), you can
calculate this using the following steps:<span>
f(0) = 2
f(n+1) = - 2 * f(n) + 3
f(1) = - 2 * f(0) + 3 = - 2 * 2 + 3 = - 4 + 3 =
- 1
f(2) = - 2 * f(1) + 3 = - 2 * (-1) + 3 = 2 + 3 =
5
The correct result would be f(2) = 5.</span>
Answer:
S=32.5
W=97.5
Step-by-step explanation:
S=speed of plane in still air
W=speed of wind
-----------------------------------------
3(S+W)=130
6(S-W)=130
-----------------------------------------
S+W=43.33333...
S-W=21.66666...
2S=64.999...
S=32.5(simplified)
-----------------------------------------
32.5+W=130
W=97.5
-----------------------------------------
Answer:
A
Step-by-step explanation:
The steps are correct! You want to get x terms on one side, numbers on the other side. You can do that by adding or subtracting both sides of the number or term you want to move.
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