Which complex number lies below the real axis and to the right of the imaginary axis?

2 answers:

8 0

To the right of the inaginar axis means the real part of a+bi is positive
below real axis means the inaginary part of a+bi is negative
a is real part
bi is imaginary part
so it should look like

a-bi

answer is B

kolezko [41]2 years ago

6 0

I believe the answer is B....

I'm glad to help ^•^

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$x =( -2 + \sqrt{2^2 - 4*1*-16}) /2*1 \\x =( -2 + \sqrt{4 + 64}) /2\\x =( -2 + \sqrt{68} )/2\\x = ( -2 + \sqrt{4*17} )/2\\x = ( -2 + 2\sqrt{17} )/2\\x = - 1 + \sqrt{17}\\and\\\\x = - 1 - \sqrt{17}\\$