14c³d²-21c²d³/14cd
= (196c^4d³-21c²d³)/ 14cd
= (196c³d²-21cd²)/14
= (28c³d²-3cd²)/2
I hope that's help !
The experimental probability is the number of specific outcomes divided by the sample size...
P(6)=27/100 (27%)
P(H)=41/100 (41%)
Not sure, but if you meant rolling a 6 AND getting a head then:
P(6 AND H)=(27/100)(41/100)=1107/10000 (11.07%)
Answer:
2w + 4
Step-by-step explanation:
2/5(5w + 10)
2w + 4 ## ^ 2/5ths of 5 is 2, and 2/5ths of 10 is 4. (Distributive POE)
Answer:
Step-by-step explanation:
For this case we have the following expression:
We need to remember that the natural log and the exponentiation with the base the euler number e are inverse operations, and if we apply exponentiation on both sides of the equation we got this:
We have the identity operator for this
And that would be our final answer for this case.