<h3>
Answer: Choice A) circle</h3>
Explanation:
Imagine that white rectangle as a blade that cuts the cylinder as the diagram shows. If you pull the top cylinder off and examine the bottom of that upper piece, then you'll see a circle forms. It's congruent to the circular face of the original cylinder. This is because the cutting plane is parallel to both base faces of the cylinder. Any sort of tilt will make an ellipse form. Keep in mind that any circle is an ellipse, but not vice versa.
Another example of a cross section: cut an orange along its center and notice that a circle (more or less) forms showing the inner part of the orange.
Yet another example of a cross section: Imagine an egyptian pyramid cut from the top most point on downward such that you vertically slice it in half. If you pull away one half, you should see a triangular cross section forms.
Answer:
Measure of ∠K=180-∠U
Or
Measure of ∠K=1/2m(arc DUC)
Step-by-step explanation:
Given:
DUCK quadrilateral inscribed in circle with center O
To Find:
Measure angle K
Solution:
Here the Quadrilateral in inscribed in a circle with center O named as DUCK
So angle K and U are opposite to each other
We know that the angle of Quadrilateral inscribed in a circle are supplemenatry angles
Hence
∠U+∠K=180
Or The ∠K=1/2*m∠arc(DUC).
Hence depending on the given value for arc measure or angle of quadrilateral we calculate the angle K
G. From the origin move right 3 units,then up 6 units
H. From the origin move left 2 units,then up 11 units
J. From the origin move right 8 units, then down 10 units
K. From the origin move left 16 units, then down 20 units
L. Plot the first point at the origin then move up 5 units
M. From the origin move left 14 units and plot the next point at the origin
Answer:
365 and 1/2 blocks will be used
The scale fact is 0.25
Step-by-step explanation:
So . .
This represents 1 block is equivalent to 2 feet
So . . There are 725 feet and because One block is equal to 2 feet you divide 725 ÷ 2 = 362.5 blocks will be used
To find the scale factor simply divide the deminsions of the new shape by old
Let x be the distance (in feet) along the road that the car has traveled and h be the distance (in feet) between the car
and the observer.
(a) Before the car passes the observer, we have dh/dt < 0; after it passes, we have dh/dt > 0. So at the instant it passes the observer we have
dh/dt = 0, given that dh/dt varies continuously since the car travels at a constant velocity.
