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borishaifa [10]

2 years ago

5

The school soccer team buys 3 soccer balls for every 2 players. The school volleyball team buys 7 volleyballs for every 5 player

s. Which team buys more balls per player?

1 answer:

SSSSS [86.1K]2 years ago

6 0

Soccer buys more; divide each

Soccer- 3/2= 1.5
Volleyball- 7/5=1.4

Soccer buys more balls per player

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PLEASE HELP!!!! Will give brainliest

pashok25 [27]

Answer:

Trapezium:

perimeter= 232

area= 2052

Triangle:

perimeter= 221

area= 4088

Step-by-step explanation:

6 0

2 years ago

Help me please I’m begging you:(

alex41 [277]

Answer:

Chips = 14

Pretzel = 14

Cookie = 8

Popcorn = 13

Question Mark = 222

Step-by-step explanation:

First Equation:

Chips + Pretzel + Chips = 42

Third Equation: Chips = Pretzel.

This means that

Pretzel + Pretzel + Pretzel = 42

Pretzel = $\frac{42}{3} =14$

Chips = Pretzel

Chips = $14$

Second Equation:

Cookie + Chips + Cookie = 30

We know that Chips = 14.

Cookie + 14 + Cookie = 30

Subtract 14 on both sides:

Cookie + Cookie = 16

Cookie = $16\div 2 =8$ .

Fourth Equation:

Cookie + Cookie + Popcorn = 29

We know that Cookie = 8.

8 + 8 + Popcorn = 29

16 + Popcorn = 29

Subtract 16 on both sides:

Popcorn = 13.

Question Mark:

(Popcorn + Popcorn) $\times$ Cookie + Chips = (13 + 13) $\times$ 8 + 14 = 26 $\times$ 8 + 14 = $208+14=222$

6 0

2 years ago

Read 2 more answers

You are arguing over a cell phone while trailing an unmarked police car by 25 m; both your car and the police car are traveling

BARSIC [14]

Answer:

(a) 15 m

(b) ground speed: 26.14 m/s (94.1 km/h); relative speed 12 m/s

Step-by-step explanation:

We can choose the frame of reference to be the trailing car. We can start counting time from the point the lead car begins deceleration. Then its position (in meters) relative to the trailing car is ...

d(t) = 25 - 5/2t² . . . . . . where 25 m is the initial distance and -5 is the acceleration in m/s².

(a) Then the distance between cars at t=2 is ...

d(2) = 25 - (5/2)·4 = 15 . . . . meters

__

(b) The <em>relative velocity</em> at 2.4 seconds is ...

d'(t) = -5t

d'(2.4) = -5(2.4) = -12.0 . . . m/s

The closure speed with the police car is 12 m/s.

__

We need to do a little more work to find the ground speed of the trailing car when the cars bump.

The distance between the cars at t=2.4 seconds is ...

d(2.4) = 25 -(5/2)2.4² = 10.6 . . . . meters

At the closure speed of 12 m/s, it will take an additional ...

10.6 m/(12 m/s) = 0.8833... s = 53/60 s

to close the gap. The speed of the trailing car at that point in time will be the original speed less the deceleration for 0.8833 seconds:

(110 km/h)·(1/3.6 (m/s)/(km/h))-(5 m/s²)(53/60 s)

= 26 5/36 m/s = 94.1 km/h

_____

<em>Comment on following distance</em>

To avoid collision, the trailing car must be trailing by at least the distance it covers in 2.4 seconds, about 73 1/3 meters.

6 0

2 years ago

Add the following quantities, 76.2 pm + 0.123fm

blondinia [14]

Answer:

m(

1000

123f

+

5

381p

)

Step-by-step explanation:

i dont know if thats right that my compution

sorry

5 0

2 years ago

A rectangular yard is fenced in using 319 feet of custom fence Your friends really like the fence and decide to fence in their y

Vsevolod [243]

We have been given that a rectangular yard is fenced in using 319 feet of custom fence Your friends really like the fence and decide to fence in their yard using the same fence. Their yard is similar but has a scale factor of 8/5 times the size of yours.

We are asked to find the length of fence that your friends should purchase.

Since the size of your friend's yard is $\frac{8}{5}$ times your yard, so your friend should purchase $\frac{8}{5}$ times the 319 feet.

$\text{Length of fence your friend should purchase}=\frac{8}{5}\times 319\text{ ft}$

$\text{Length of fence your friend should purchase}=8\times 63.8\text{ ft}$

$\text{Length of fence your friend should purchase}=510.4\text{ ft}$

Upon rounding our answer to nearest foot, we will get:

$\text{Length of fence your friend should purchase}\approx 510\text{ ft}$

Therefore, your friends should purchase 510 feet of fence and option C is the correct choice.

5 0

2 years ago