Answer:
Decentralized control
Explanation:
Decentralized control -
It refers to the method adapted by the organisation or company , in which the lower level elements helps completely to attain certain goal or task , is referred to as decentralization control
In this case , the people in the higher post need not rule over the lower one to complete the project or task on time .
The company using this method is happy as the employees are hardworking and there is least number of arguments , and hence becomes successful in shorter run .
Hence , from the question ,
The correct term is decentralization control .
Answer:
<u><em>Total expenses 936,500</em></u>
depreciation 291,500
wages expense 645,000
Explanation:
Assuming the depreciation are calculate base on straight line or that their output is lineal through the year:
It will be half of the depreciation for the year.
583,000 / 2 = 291,500 depreciation expense for six-month
For the year-end bonused It wll be the same ideal, we assume are earned equally during the year. So at half year half of the bonuses should be earned:
wages expense 1,290,000/2 = 645,000
<u>Total expenses 936,500</u>
Answer:
This is true
Explanation:
Sarah illustrated scaffolding for Haley by supporting her through learning when putting lace around the card's edge.
Answer:
- <em>As explained below, given that the score of the person is among the 0.03125 fraction of the best applicants, </em><u><em>he can count on getting one of the jobs.</em></u>
<em></em>
Explanation:
The hint is to use <em>Chebyshev’s Theorem.</em>
Chebyshev’s Theorem applies to any data set, even if it is not bell-shaped.
Chebyshev’s Theorem states that at least 1−1/k² of the data lie within k standard deviations of the mean.
For this sample you have:
- mean: 60
- standard deviation: 6
- score: 84
The number of standard deviations that 84 is from the mean is:
- k = (score - mean) / standar deviation
- k = (84 - 60) / 6 = 24 / 6 = 4
Thus, the score of the person is 4 standard deviations above the mean.
How good is that?
Chebyshev’s Theorem states that at least 1−1/k² of the data lie within k standard deviations of the mean. For k = 4, that is:
- 1 - 1/4² = 1 - 1/16 = 0.9375
- That means that half of 1 - 0.9375 are above k = 4: 0.03125
- Then, 1 - 0.03125 are below k = 4: 0.96875
Since there are 70 positions and 1,000 aplicants, 70/1,000 = 0.07. The compnay should select the best 0.07 of the applicants.
Given that the score of the person is among the 0.03125 upper fraction of the applicants, this person can count of geting one of the jobs.
