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2 years ago

ASAP

1 answer:

5 0

The given regression shows the relationship between the numbers of car washed(x) and the amount earned for charity(y).

y = 10x + 20

We are to calculate the amount of charity if 50 cars are washed. Number of cars are represented by x, so by substituting x = 50 in above equation we can find the amount of charity that is earned by washing 50 cars.

y = 10(50) + 20 = $ 520

Thus, the charity can earn $520 if 50 cars come in for a wash.

You might be interested in

Write an equivalent expression for the expression shown below:<br><br> a/3 + a/3 + a/3

iris [78.8K]

Answer:

3 (a/3) = a

Step-by-step explanation:

a/3 + a/3 + a/3

3 times a/3

the 3's cancel each other out

Keep up the good work! =)

3 0

3 years ago

The trail of boeing is 63 2/3 feet how many inches tall is the trail

NemiM [27]

We know that

<span>63 2/3 feet----------------> (63*3+2)/3---------> 191/3 ft
</span>
1 ft-----------------> 12 in
191/3 ft----------------> X in
X=(191/3)*12------------> X=764 in

the answer is 764 in

5 0

2 years ago

Someone give me an easy algebra problem thx

likoan [24]

Answer:

write the equation of the line that passes through (7,6) and (-1,2) in a slope intercept form.

7 0

2 years ago

WILL GIVE BRAINLIEST

myrzilka [38]

Answer:

$\sqrt{11}$

Step-by-step explanation:

The square root of 11 is 3.31... this could be the answer.

3 0

2 years ago

Considering only the values of β for which sinβtanβsecβcotβ is defined, which of the following expressions is equivalent to sinβ

-Dominant- [34]

Answer:

$\tan(\beta)$

Step-by-step explanation:

For many of these identities, it is helpful to convert everything to sine and cosine, see what cancels, and then work to build out to something. If you have options that you're building toward, aim toward one of them.

${\tan(\theta)}={\dfrac{\sin(\theta)}{\cos(\theta)}$ and ${\sec(\theta)}={\dfrac{1}{\cos(\theta)}$

Recall the following reciprocal identity:

$\cot(\theta)=\dfrac{1}{\tan(\theta)}=\dfrac{1}{ \left ( \dfrac{\sin(\theta)}{\cos(\theta)} \right )} =\dfrac{\cos(\theta)}{\sin(\theta)}$

So, the original expression can be written in terms of only sines and cosines:

$\sin(\beta)\tan(\beta)\sec(\beta)\cot(\beta)$

$\sin(\beta) * \dfrac{\sin(\beta) }{\cos(\beta) } * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) } {\sin(\beta) }$

$\sin(\beta) * \dfrac{\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} {\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}$

$\sin(\beta) *\dfrac{1 }{\cos(\beta) }$

$\dfrac{\sin(\beta)}{\cos(\beta) }$

Working toward one of the answers provided, this is the tangent function.

The one caveat is that the original expression also was undefined for values of beta that caused the sine function to be zero, whereas this simplified function is only undefined for values of beta where the cosine is equal to zero. However, the questions states that we are only considering values for which the original expression is defined, so, excluding those values of beta, the original expression is equivalent to $\tan(\beta)$ .

8 0

1 year ago