6x+18=h(3x+9) what value the constant h in the equation shown below will result in a infinite number of solutions
2 answers:
Answer:
h = 2
Step-by-step explanation:
6x + 18 = h (3x + 9)
To get the value of h, we simply need to make h subject of the formula;
To make h subject of the formula, we simply divide both-side of the equation by (3x + 9)
=
(On the right hand side of the equation (3x+2) will cancel out (3x+2) leaving us with h)
= h
h = ----------------(1)
We want to make the numerator and denominator look the same so that we can cancel out, at the numerator, we can factor out 2 from 6x + 18
i.e 6x + 18 = 2 ( 3x + 9)
So we can replace 6x + 18 by 2(3x + 9) in equation (1)
h =
( on the right hand side of the equation, (3x + 9) will cancel out (3x + 9) leaving us with just 2)
<em>h = 2</em>
We can plug in our h =2 in the initial equation
6x + 18 = 2(3x + 9)
6x + 18 = 6x + 18
This equation has an infinite number of solutions.
Therefore the value of constant h in the equation that can make the equation have an infinite number of solutions is 2
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Answer:
Z= (X1`-X2`)- (u1-u2)/ (here s1=σ1 and s2= σ2)
Step-by-step explanation:
Let X1` be the mean of the first random sample of size n1 from a normal population with a mean u1 and known standard deviation σ1.Let X2` be the mean of the second random sample of size n2 from another normal population with a mean u2 and known standard deviation σ2. Then the sampling distribution of the difference X1`-X2` is normally distributed with a mean of u1-u2 and a standard deviation of
. (here s1=σ1 and s2= σ2) In other words the variable
Z= (X1`-X2`)- (u1-u2)/ (here s1=σ1 and s2= σ2)
is exactly standard normal no matter how small sample sizes are . Hence it is used as a test statistic for testing hypotheses about the difference between two population means.
The procedure is stated below.
1) Formulate the null and alternative hypotheses.
2) Decide on significance level ∝
3) Use the test statistic Z= (X1`-X2`)- (u1-u2)/ (here s1=σ1 and s2= σ2)
4) Find the rejection region
5)Compute the value of Z from the sample data
6) Rehect H0 if Z falls in the critical region, accept H0 , otherwise.